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\begin{aligned} W_{\mathrm{app}} &=F_{\mathrm{app}} d \cos \left(0^{\circ}\right)=F_{\mathrm{app}} d \\ &=(120 \mathrm{~N})(0.800 \mathrm{~m}) \\ &=96.0 \mathrm{~J} \end{aligned}