TeX source:

P(A|B) = \dfrac{P(A∩B)}{P(B)} =\dfrac{\dfrac {\text {(the number of outcomes that are 2 or 3 and even in S)}}{6}}{\dfrac {\text {(the number of outcomes that are even in S)}}{6}}= \dfrac{\dfrac{1}{6}}{\dfrac{3}{6}}=\dfrac{1}{3}