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=\frac{1}{9} \int_{0}^{9} 5+\mathrm{t}^{1 / 2} \mathrm{dt}=\left.\frac{1}{9}\left(5 \mathrm{t}+\frac{2}{3} \mathrm{t}^{3 / 2}\right)\right|_{0} ^{9}