TeX source:

\begin{aligned}P(\bar{X} > 113) &=P\left(Z > \frac{113-\mu_{X}}{\sigma_{X}}\right) \\&=P\left(Z > \frac{113-112}{5.65685}\right) \\&=P(Z > 0.18) \\&=1-P(Z < 0.18)=1-0.5714=0.4286\end{aligned}