TeX source:

\begin{array}{ll} log_2(15x(x−1))−log_2((3x+4)(2−x)) &=[log_2(3)+log_2(5)+log_2(x)+log_2(x−1)]−[log_2(3x+4)+log_2(2−x)] \\ &=log_2(3)+log_2(5)+log_2(x)+log_2(x−1)−log_2(3x+4)−log_2(2−x) \end{array}