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\begin{array}{ll}\sin \left(5.0^{\circ}\right) & =\frac{T_{\mathrm{L} y}}{T_{\mathrm{L}}} \\T_{\mathrm{L} y}=T_{\mathrm{L}} \sin \left(5.0^{\circ}\right) & =T \sin \left(5.0^{\circ}\right) \\\sin \left(5.0^{\circ}\right) & =\frac{T_{\mathrm{R} y}}{T_{\mathrm{R}}} \\T_{\mathrm{R} y}=T_{\mathrm{R}} \sin \left(5.0^{\circ}\right) & =T \sin \left(5.0^{\circ}\right)\end{array}