TeX source:

\int_{0}^{2}\left(x^{2}-1\right) \mathrm{dx}=\frac{x^{3}}{3}-x+\left.4\right|_{0} ^{2}=\left(\frac{2^{3}}{3}-2+4\right)-\left(\frac{0^{3}}{3}-0+4\right)=14 / 3- 4 = 2/3