Practice Solving One-Step Inequalities
Practice Problems
Answers
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To isolate \(x\), let's divide both sides by 9.
\(\dfrac{-18}{9} < \dfrac{9x}{9}\)
Now, we simplify!
\(-2 < x\) or \(x > -2\)
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To isolate \(x\), let's subtract -4 from both sides.
\(-4-(-4)+x\leq9-(-4)\)
Now, we simplify!
\(x\leq13\)
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To isolate \(x\), let's divide both sides by -7.
Remember that when we divide (or multiply) an inequality by a negative number, we have to flip the direction of the inequality.
\(\begin{aligned}
-7x& > 10\\\\
\dfrac{-7x}{-7}& < \dfrac{10}{-7}
\end{aligned}\)Now, we simplify!
\( x < - \dfrac{10}{7} \)
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To isolate \(x\), let's multiply both sides by 7.
\(\dfrac x 7\cdot7\geq-6\cdot7\)
Now, we simplify!
\(x\geq-42\)
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To isolate \(x\), let's add 10 to both sides.
\(-3+10 < x-10+10\)
Now, we simplify!
\(7 < x\) or \(x > 7\)
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To isolate \(x\), let's divide both sides by -1.
Remember that when we divide (or multiply) an inequality by a negative number, we have to flip the direction of the inequality.\(\begin{aligned}
-x& < -29\\\\
\dfrac{-x}{-1}& > \dfrac{-29}{-1}
\end{aligned}\)Now, we simplify!
\(x > 29\)
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To isolate \(x\), let's multiply both sides by 4.
\(7\cdot4>\dfrac{x}{4}\cdot4\)
Now, we simplify!
\(28 > x\) or \(x < 28\)