Practice Solving One-Step Inequalities

Practice Problems

Answers

  1. To isolate ‍\(x\), let's divide both sides by ‍9.

    \(\dfrac{-18}{9} < \dfrac{9x}{9}\)

    Now, we simplify!

    \(-2 <  x\) or \(x > -2\)

  2. To isolate ‍\(x\), let's subtract -4 from both sides.

    \(-4-(-4)+x\leq9-(-4)\)

    Now, we simplify!

    \(x\leq13\)

  3. To isolate ‍\(x\), let's divide both sides by ‍-7.

    Remember that when we divide (or multiply) an inequality by a negative number, we have to flip the direction of the inequality.

    \(\begin{aligned}
    -7x& > 10\\\\
    \dfrac{-7x}{-7}& < \dfrac{10}{-7}
    \end{aligned}\)

    Now, we simplify!

    \( x < - \dfrac{10}{7} \)

  4. To isolate ‍\(x\), let's multiply both sides by ‍7.

    \(\dfrac x 7\cdot7\geq-6\cdot7\)

    Now, we simplify!

    \(x\geq-42\)

  5. To isolate ‍\(x\), let's add 10 to both sides.

    \(-3+10 < x-10+10\)

    Now, we simplify!

    \(7 < x\) or \(x > 7\)

  6. To isolate ‍\(x\), let's divide both sides by ‍-1.

    Remember that when we divide (or multiply) an inequality by a negative number, we have to flip the direction of the inequality.

    \(\begin{aligned}
    -x& < -29\\\\
    \dfrac{-x}{-1}& > \dfrac{-29}{-1}
    \end{aligned}\)

    Now, we simplify!

    \(x > 29\)

  7. To isolate ‍\(x\), let's multiply both sides by ‍4.

    \(7\cdot4>\dfrac{x}{4}\cdot4\)

    Now, we simplify!

    \(28 > x\) or \(x < 28\)