Review of One-Step Inequalities

Site: Saylor Academy
Course: GKT101: General Knowledge for Teachers – Math
Book: Review of One-Step Inequalities
Printed by: Guest user
Date: Sunday, May 19, 2024, 5:15 PM

Description

Watch this lecture series and complete the interactive exercises to review how to solve, graph, and represent the solutions to one-step inequalities.

One-step inequalities: -5c ≤ 15

One-step inequality involving addition

One-step inequality word problem

Inequalities using addition and subtraction

Solving and graphing linear inequalities

One-step inequalities - Questions

1. Solve for x.
Your answer must be simplified.

-18 < 9 x


2. Solve for x.
Your answer must be simplified.

x-24 \geq 9


3. Solve for x.
Your answer must be simplified.

\frac{x}{-6} \geq-20


4. Solve for x.
Your answer must be simplified.

\frac{x}{3} \geq-33


5. Solve for x.
Your answer must be simplified.

x-15 \leq-6


6. Solve for x.
Your answer must be simplified.

-14 x >-3


7. Solve for x.
Your answer must be simplified.

\frac{x}{25} > 5

Answers

1. -2 < x or x > -2

To isolate x, let's divide both sides by 9.

\frac{-18}{9} < \frac{9 x}{9}

Now, we simplify!

  • -2 < x or
  • x > -2


2. x \geq 33

To isolate x, let's add 24 to both sides.

x-24+24 \geq 9+24

Now, we simplify!

x \geq 33


3. x \leq 120

To isolate x, let's multiply both sides by -6.

Remember that when we multiply (or divide) an inequality by a negative number, we have to flip the direction of the inequality.

\frac{x}{-6} \cdot-6 \leq-20 \cdot-6

Now, we simplify!

x \leq 120


4. x \geq-99

To isolate x, let's multiply both sides by 3.

\frac{x}{3} \cdot 3 \geq-33 \cdot 3

Now, we simplify!

x \geq-99


5. x \leq 9

To isolate x, let's add 15 to both sides.

x-15+15 \leq-6+15

Now, we simplify!

x \leq 9


6. x < \frac{3}{14}

To isolate x, let's divide both sides by -14.

Remember that when we divide (or multiply) an inequality by a negative number, we have to flip the direction of the inequality.

-14 x >-3

\frac{-14 x}{-14}

Now, we simplify!

x < \frac{3}{14}


7. x > 125

To isolate x, let's multiply both sides by 25.

\frac{x}{25} \cdot 25 > 5 \cdot 25

Now, we simplify!

x > 125