Graphing Slope-Intercept Equations

Site: Saylor Academy
Course: GKT101: General Knowledge for Teachers – Math
Book: Graphing Slope-Intercept Equations
Printed by: Guest user
Date: Tuesday, 20 May 2025, 8:11 AM

Description

As you have seen from examples, you can write linear equations in different ways. There are three main forms of linear equations: slope-intercept, point-slope, and standard. This lecture series introduces the point-slope form. Watch the videos and complete the interactive exercises. This lecture series focuses on graphing linear equations when they are given in slope-intercept form.

Graph from slope-intercept form - Questions

1. Graph \(y=-x-6\).


2. Graph \(y=\frac{2}{3} x-4\)


3.Graph \(y=-3 x+7\).


4. Graph \(y=\frac{6}{5} x+1\).

Answers

1. The equation is in slope-intercept form: \(y=m \cdot x+b\). In this form, \(m\) gives us the slope of the line and \(b\) gives us its \(y\)-intercept.

So \(y=-x-6\) has a slope of \(-1\) and a \(y\)-intercept at \( (0,-6)\).

We need two points. We already have the \(y\)-intercept \((0,-6)\).

We can find a second point by reasoning about the slope. A slope of \(-1\) means when the \(x\)-value increases by \(1\), the \(y\)-value decreases by \(1\).

\((0+1,-6-1)=(1,-7)\)


Now we can graph the equation.



2. The equation is in slope-intercept form: \(y=m \cdot x+b\). In this form, \(m\) gives us the slope of the line and \(b\) gives us its \(y\)-intercept.

So \(y=\frac{2}{3} x-4\) has a slope of \(\frac {2}{3}\) and a \(y\)-intercept of \((0. -4)\).

We need two points. We already have the \(y\)-intercept \((0,-4)\).

We can find a second point by reasoning about the slope. A slope of \(\frac{2}{3}\) means that when the \(x\)-value increases by \(3\), the \(y\)-value increases by \(2\).

\((0+3,-4+2)=(3,-2)\)

Now we can graph the equation.


3. The equation is in slope-intercept form: \(y=m \cdot x+b\). In this form, \(m\) gives us the slope of the line and \(b\) gives us its \(y\)-intercept.

So \(y = -3x+7\) has a slope of \(-3\) and a \(y\)-intercept at \((0,7)\).

We need two points. We already have the \(y\)-intercept \((0,7)\).

We can find a second point by reasoning about the slope. A slope of \(-3\) means that when the \(x\)-value increases by \(1\), the \(y\)-value decreases by \(3\).

\((0+1,7-3)=(1,4)\)

Now we can graph the equation.


4. The equation is in slope-intercept form: \(y=m \cdot x+b\). In this form, \(m\) gives us the slope of the line and \(b\) gives us its \(y\)-intercept.

So \(y=\frac{6}{5} x+1\) has a slope of \(\frac{6}{5}\) and a \(y\)-intercept at \((1, 0)\).

We need two points. We already have the \(y\)-intercept \((0,1)\).

We can find a second point by reasoning about the slope. A slope of \(\frac {6}{5}\) means that when the \(x\)-value increases by \(5\), the \(y\)-value increases by \(6\).

\((0+5,1+6)=(5,7)\)

Now we can graph the equation.