Practice Solving One-Step Inequalities

Site: Saylor Academy
Course: MA007: Algebra
Book: Practice Solving One-Step Inequalities
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Date: Tuesday, 15 July 2025, 7:47 AM

Description

Table of contents

Practice Problems

Solve for \(x\)

Your answer must be simplifies

  1. \(-18 < 9x\)

  2. \(-4+x\leq9\)

  3. \(-7x > 10\)

  4. \(\dfrac x 7\geq-6\)

  5. \(-3 < x-10\)

  6. \(-x < -29\)

  7. \(7 > \dfrac x4\)


Source: Khan Academy, https://www.khanacademy.org/math/algebra-basics/alg-basics-linear-equations-and-inequalities/alg-basics-one-step-inequalities/e/one_step_inequalities
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Answers

  1. To isolate ‍\(x\), let's divide both sides by ‍9.

    \(\dfrac{-18}{9} < \dfrac{9x}{9}\)

    Now, we simplify!

    \(-2 <  x\) or \(x > -2\)

  2. To isolate ‍\(x\), let's subtract -4 from both sides.

    \(-4-(-4)+x\leq9-(-4)\)

    Now, we simplify!

    \(x\leq13\)

  3. To isolate ‍\(x\), let's divide both sides by ‍-7.

    Remember that when we divide (or multiply) an inequality by a negative number, we have to flip the direction of the inequality.

    \(\begin{aligned}
    -7x& > 10\\\\
    \dfrac{-7x}{-7}& < \dfrac{10}{-7}
    \end{aligned}\)

    Now, we simplify!

    \( x < - \dfrac{10}{7} \)

  4. To isolate ‍\(x\), let's multiply both sides by ‍7.

    \(\dfrac x 7\cdot7\geq-6\cdot7\)

    Now, we simplify!

    \(x\geq-42\)

  5. To isolate ‍\(x\), let's add 10 to both sides.

    \(-3+10 < x-10+10\)

    Now, we simplify!

    \(7 < x\) or \(x > 7\)

  6. To isolate ‍\(x\), let's divide both sides by ‍-1.

    Remember that when we divide (or multiply) an inequality by a negative number, we have to flip the direction of the inequality.

    \(\begin{aligned}
    -x& < -29\\\\
    \dfrac{-x}{-1}& > \dfrac{-29}{-1}
    \end{aligned}\)

    Now, we simplify!

    \(x > 29\)

  7. To isolate ‍\(x\), let's multiply both sides by ‍4.

    \(7\cdot4>\dfrac{x}{4}\cdot4\)

    Now, we simplify!

    \(28 > x\) or \(x < 28\)