Summation Notation Practice

Site: Saylor Academy
Course: MA120: Applied College Algebra
Book: Summation Notation Practice
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Date: Saturday, 3 May 2025, 2:32 PM

Description

Table of contents

Practice Problems

  1. \large\displaystyle\sum\limits_{k=1}^{2 }{{(3-k)}}=

  2. \large\displaystyle\sum\limits_{n=0}^{2 }{{(-n)}}=

  3. \large\displaystyle\sum\limits_{x=1}^{2 }{{(6x)}}=

  4. \large\displaystyle\sum\limits_{n=0}^{2 }{{(n)}}=

Source: Khan Academy, https://www.khanacademy.org/math/precalculus/x9e81a4f98389efdf:series/x9e81a4f98389efdf:geo-series-notation/e/evaluating-basic-sigma-notation
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Answers

  1. What is the question asking for?

    \sum tells us to find the sum.

    The question is asking for the sum of the values of ‍3-k from ‍k = 1 to ‍k = 2.

    Evaluating

    \begin{aligned} \large\displaystyle\sum\limits_{k=1}^{2 }{({3-k})}&= (3-1) + (3-2) \\\\&= 2 + 1 \\\\&= 3\end{aligned}

    The answer

    \large\displaystyle\sum\limits_{k=1}^{2 }{({3-k})}=3


  2. What is the question asking for?

    \sum tells us to find the sum.

    The question is asking for the sum of the values of ‍3-n from ‍n = 0 to ‍n = 2.

    Evaluating

    \begin{aligned} \large\displaystyle\sum\limits_{n=0}^{2 }{({-n})}&= (-0) + (-1) + (-2) \\\\&= 0 + (-1) + (-2) \\\\&= -3\end{aligned}

    The answer

    \large\displaystyle\sum\limits_{n=0}^{2 }{({-n})}=-3


  3. What is the question asking for?

    \sum tells us to find the sum.

    The question is asking for the sum of the values of ‍6x from ‍x = 1 to ‍x = 2.

    Evaluating

    \begin{aligned} \large\displaystyle\sum\limits_{x=1}^{2 }{({6x})}&= (6(1)) + (6(2)) \\\\&= 6 + 12 \\\\&= 18\end{aligned}

    The answer

    \large\displaystyle\sum\limits_{x=1}^{2 }{({6x})}=18


  4. What is the question asking for?

    \sum tells us to find the sum.

    The question is asking for the sum of the values of ‍3-n from ‍n = 0 to ‍n = 2.

    Evaluating

    \begin{aligned} \large\displaystyle\sum\limits_{n=0}^{2 }{({n})}&= (0) + (1) + (2) \\\\&= 0 + 1 + 2 \\\\&= 3\end{aligned}

    The answer

    \large\displaystyle\sum\limits_{n=0}^{2 }{({n})}=3