Writing Equations of Lines Practice

Site: Saylor Academy
Course: MA120: Applied College Algebra
Book: Writing Equations of Lines Practice
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Date: Saturday, 3 May 2025, 2:24 PM

Description

Table of contents

Practice Problems

  1. Complete the equation of the line through (-1,6) and (7,-2).

    Use exact numbers.

    y= 

  2. Complete the equation of the line through (3,-1) and (4,7).

    Use exact numbers.

    y=

  3. Complete the equation of the line through (-10,-7) and [(-5,-9)\).

    Use exact numbers.

    y=

  4. Complete the equation of the line through (4,-8) and (8,5).

    Use exact numbers.

    y=


Source: Khan Academy, https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:forms-of-linear-equations/x2f8bb11595b61c86:writing-slope-intercept-equations/e/slope-intercept-equation-from-two-points
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Answers

  1. Let's find the slope:

    \begin{aligned}\text{Slope}&=\dfrac{-2-6}{7-(-1)}\\\\&=\dfrac{-8}{8}\\\\&=-1\end{aligned}

    The equation is y=-1x+b for some b.

    Let's plug the point ( {7}, {-2}) to find b:

    \begin{aligned} y&=-1 x+b\\\\ {-2}&=-1( {7})+b\\\\-2&=-7+b\\\\5&=b\end{aligned}

    The equation is y=-x +5.


  2. Let's find the slope:

    \begin{aligned}\text{Slope}&=\dfrac{7-(-1)}{4-3}\\\\&=\dfrac{8}{1}\\\\&=8\end{aligned}

    The equation is y=8x+b for some b.

    Let's plug the point ( {4}, {7}) to find b:

    \begin{aligned} y&=8 x+b\\\\ {7}&=8( {4})+b\\\\7&=32+b\\\\-25&=b\end{aligned}

    The equation is y=8x -25.


  3. Let's find the slope:

    \begin{aligned}\text{Slope}&=\dfrac{-9-(-7)}{-5-(-10)}\\\\&=\dfrac{-2}{5}\\\\&=-\dfrac{2}{5}\end{aligned}

    The equation is y=-\dfrac{2}{5}x+b for some b.

    Let's plug the point ( {-5}, {-9}) to find b:

    \begin{aligned} y&=-\dfrac{2}{5} x+b\\\\ {-9}&=-\dfrac{2}{5}( {-5})+b\\\\-9&=2+b\\\\-11&=b\end{aligned}

    The equation is y=-\dfrac{2}{5}x -11.


  4. Let's find the slope:

    \begin{aligned}\text{Slope}&=\dfrac{5-(-8)}{8-4}\\\\&=\dfrac{13}{4}\end{aligned}

    The equation is y=\dfrac{13}{4}x+b for some b.

    Let's plug the point ( {8}, {5}) to find b:

    \begin{aligned} y&=\dfrac{13}{4} x+b\\\\ {5}&=\dfrac{13}{4}( {8})+b\\\\5&=26+b\\\\-21&=b\end{aligned}

    The equation is y=\dfrac{13}{4}x -21.