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Review
Answers
Part 1
\(y+4=\frac{1}{3}(x-0) \quad\) or \(\quad y+4=\frac{1}{3} x\)
- \(y-2=-\frac{1}{10}(x-10)\)
\(y-3=-5(x+2) \quad\) or \(\quad y+2=-5(x+1)\)
\(y-0=2(x-0)\) or \(y-2=2(x-1)\)
Part 2
\(y=3 x-1\)
- \(y=-\frac{2}{3} x-8\)