Applications of Linear Equations

This section this textbook explains how to translate the situations described in word problems to equations and provides a variety of examples. Read the chapter and work through the problems. Some examples involved the geometric facts you have learned in Unit 2.

Example 108.

The perimeter of a rectangle is 44. The length is 5 less than double the width. Find the dimensions.

Length x We will make the length x
Width 2x − 5 Width is five less than two times the length
P =2L + 2W The formula for perimeter of a rectangle
(44) =2(x)+ 2(2x − 5) Replace P, L, and W with labeled values
44 = 2x +4x − 10 Distribute through parenthesis
 44 =6x − 10 Combine like terms 2x +4x
\underline {+ 10 + 10} Add 10 to both sides
 \underline {54 =6x} The variable is multiplied by 6
6 \quad \quad 6 Divide both sides by 6
9= x Our solution for x
Length 9 Replace x with 9 in the original list of sides
Width 2(9) − 5 = 13 The dimensions of the rectangle are 9 by 13.


We have seen that it is important to start by clearly labeling the variables in a short list before we begin to solve the problem. This is important in all word problems involving variables, not just consecutive numbers or geometry problems. This is shown in the following example.