# Truth Tables and De Morgan's Rules

## 18. More De Morgan

Answer:Using the De Morgan Rule!(A && B) is equivalent to !A || !BThe expressionboolean discount =  !( (days < 14) && onSeason );is equivalent toboolean discount =  !(days < 14) || !onSeason ; which can be further transformed toboolean discount =  days >= 14  || !onSeason ;

# More De Morgan

De Morgan's rules can be extended to three operands:

!(A && B && C) is equivalent to !A || !B || !C
!(A || B || C) is equivalent to !A && !B && !C

Expressions with more than three operands behave similarly.

Question 18:A driver holding a learner's permit may drive a car only during daylight hours and  only if accompanied by a licensed driver of age 21 or over.boolean drivingOK = daylight && passenger.age >= 21  && passenger.licensed;Assume that passenger refers to an object with an integer member age
and a boolean member licensed.Here is an expression that says when driving is not permitted:boolean noDriving = !(daylight && passenger.age >= 21  && passenger.licensed );Transform this into a simpler expression.