Definition of a Limit
Site: | Saylor Academy |
Course: | MA005: Calculus I |
Book: | Definition of a Limit |
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Date: | Friday, May 17, 2024, 4:16 AM |
Description
Read this section to learn how a limit is defined. Work through practice problems 1-6.
Definition of Limit
It may seem strange that we have been using and calculating the values of limits for a while without having a precise definition of limit, but the history of mathematics shows that many concepts, including limits, were successfully used before they were precisely defined or even fully understood. We have chosen to follow the historical sequence in this chapter and to emphasize the intuitive and graphical meaning of limit because most students find these ideas and calculations easier than the definition. Also, this intuitive and graphical understanding of limit was sufficient for the first hundred years of the development of calculus (from Newton and Leibniz in the late 1600's to Cauchy in the early 1800's), and it is sufficient for using and understanding the results in beginning calculus.
Mathematics, however, is more than a collection of useful tools, and part of its power and beauty comes from the fact that in mathematics terms are precisely defined and results are rigorously proved. Mathematical tastes (what is mathematically beautiful, interesting, useful) change over time, but because of these careful definitions and proofs, the results remain true, everywhere, and forever. Textbooks seldom give all of the definitions and proofs, but it is important to mathematics that such definitions and proofs exist.
The goal of this section is to provide a precise definition of the limit of a function. The definition will not help you calculate the values of limits, but it provides a precise statement of what a limit is. The definition of limit is then used to verify the limits of some functions, and some general results are proved.
Source: Dave Hoffman, https://s3.amazonaws.com/saylordotorg-resources/wwwresources/site/wp-content/uploads/2012/12/MA005-2.5-Definition-of-Limit.pdf
This work is licensed under a Creative Commons Attribution 3.0 License.
The Intuitive Approach
The precise ("formal") definition of limit carefully defines the ideas that we have already been using graphically and intuitively. The following side–by–side columns show some of the phrases we have been using to describe limits, and those phrases, particularly
the last ones, provide the basis to building the definition of limit.
Let's examine what the last phrase ("we can.."). means for the Particular Limit.
Example 1: We know . Show that we can guarantee that the values of are as close to 5 as we want by starting with values of sufficiently close to 3.
(a) What values of guarantee that is within unit of ? (Fig. 1a)
Solution: "within unit of " means between and , so the question can be rephrased as "for what values of is between 4 and ? We want to know which values of put the values of into the shaded band in Fig. 1a. The algebraic process is straightforward: solve for to get and . We can restate this result as follows: "If is within units of 3, then is within unit of ". (Fig. 1b)
Any smaller distance also satisfies the guarantee: e.g., "If is within units of 3, then is within 1 unit of 5". (Fig. 1c)
(b) What values of guarantee the is within units of ? (Fig. 2a)
Solution: "within units of 5" means between and , so the question can be rephrased as "for what values of is between and 5.2: ?" Solving for , we get and . "If is within units of 3, then is within units of " (Fig. 2b) Any smaller distance also satisfies the guarantee.
Rather than redoing these calculations for every possible distance from 5, we can do the work once, generally:
(c) What values of guarantee that is within units of 5? (Fig. 3a)
Solution: "within unit of 5" means between and , so the question is "for what values of is between and ?" Solving for get and . "If is within units of 3, then is within units of 5". (Fig. 3b) Any smaller distance also satisfies the guarantee.
Part (c) of Example 1 illustrates a little of the power of general solutions in mathematics. Rather than doing a new set of similar calculations every time someone demands that be within some given distance of 5, we did the calculations once. And then we can respond for any given distance. For the question "What values of guarantee that is within and units of 5?", we can answer "If is within and units of 3".
Practice 1: . What values of guarantee that is within
(a) 1 unit of 3?
(b) 0.08 units of 3?
(c) E units of 3? (Fig. 4)
The same ideas work even if the graphs of the functions are not straight lines, but the calculations are more complicated.
Example 2: (a) What values of guarantee that is within unit of ? (b) Within units of ?
(Fig. 5a) State each answer in the form "If is within _____ units of , then is within (or unit of ".
Solution; (a) If is within unit of , then so
or . The interval containing these values extends from units to the left of to units to the right of 2. Since we want to specify a single distance on each side of , we can pick the smaller of the two distances, . (Fig. 5b)
"If is within units of , then is within unit of ".
(b) Similarly, if is within units of 4, then so or . The interval containing these values extends from units to the left of 2 to units to the right of 2. Again picking the smaller of the two distances, "If is within units of , then is within unit of ".
The situation in Example 2 of different distances on the left and right sides is very common, and we always pick our single distance to be the smaller of the distances to the left and right. By using the smaller distance, we can be certain that if is within that smaller distance on either side, then the value of is within the specified distance of the value of the limit.
Practice 2: . What values of guarantee that is within 1 unit of 3? Within units of 3? (Fig. 6) State each answer in the form.
"If is ______ within units of 2, then is within 1 (or 0.2) unit of 4".
The same ideas can also be used when the function and the specified distance are given graphically, and in that case we can give the answer graphically.
Example 3: In Fig. 7, . What values of guarantee that is within units (given graphically) of 3? State your answer in the form "If is within _____ (show a distance D graphically) of 2, then is within units of 3".
Solution: The solution process requires several steps as illustrated in Fig. 8:
i. Use the given distance to find the values and on the -axis.
ii. Sketch the horizontal band which has its lower edge at and its upper edge at .
iii. Find the first locations to the right and left of where the graph of crosses the lines and and at these locations draw vertical lines to the -axis.
iv. On the -axis, graphically determine the distance from to the vertical line on the left (labeled and from 2 to the vertical line on the right (labeled .
v. Let the length be the smaller of the lengths and .
Practice 3: In Fig. 9, . What of guarantee that is within E units of ?
The Formal Definition of Limit
The ideas of the previous examples and practice problems can be stated for general functions and limits, and they provide the basis for the definition of limit which is given in the box. The use of the lower case Greek letters (epsilon)
and (delta) in the definition is standard, and this definition is sometimes called the "epsilon-delta" definition of limit.
In this definition, represents the given distance on either side of the limiting value , and is the distance on each side of the point on the -axis that we have been finding in the previous
examples. This definition has the form of a "challenge and reponse:" for any positive challenge (make within of ), there is a positive response (start with
within of and ).
Example 4: In Fig. 11a, , and a value for is given graphically as a length. Find a length for that satisfies the definition
of limit (so "if is within of and , then is within of ").
Solution: Follow the steps outlined in Example 3. The length for is shown in Fig. 11b, and any shorter length for also satisfies the definition.
Practice 4: In Fig. 12, , and a value for is given graphically as a length. Find a length for that satisfies the definition of limit.
Solution: We need to show that
"for every given there is a so that
Actually there are two things we need to do. First, we need to find a value for (typically depending on ), and, second, we need to show that our really does satisfy the "if then" part of the definition.
i. Finding is similar to part (c) in Example 1 and Practice 1: assume is within units of 7 and solve for . If , then and , so is within units of 3. Put
ii. To show that satisfies the definition, we merely reverse the order of the steps in part i. Assume that is within units of 3. Then so
we can conclude that is within units of 7. This formally verifies that .
The method used to prove the values of the limits for these particular linear functions can also be used to prove the following general result about the limits of linear functions.
Case 1: . Then is simply a constant function, and any value for satisfies the definition. Given any value of , let (any positive value for works). If is is within 1 unit of , then , so we have shown that for any , there is a which satisfies the definition.
Case 2: . Then . For any , put . If is within of , then
Then the distance between and is so is within of . (Fig. 13)
In each case, we have shown that "given any , there is a " that satisfies the rest of the definition is satisfied.
If there is even a single value of for which there is no , then the function does not satisfy the definition, and we say that the limit "does not exist".
Example 6: Let as is shown in Fig. 14.
Use the definition to prove that does not exist.
Solution: One common proof technique in mathematics is called "proof by contradiction," and that is the method we use here. Using that method in this case, (i) we assume that the limit does exist and equals some number , (ii) we show that this assumption leads to a contradiction, and (iii) we conclude that the assumption must have been false. Therefore, we conclude that the limit does not exist.
(i) Assume that the limit exists: for some value for . Let . (The definition says "for every ε" so we can pick this value. Why we chose this value for shows up later in the proof). Then, since we are assuming that the limit exists, there is a so that if is within of 1 then is within of .
(ii) Let be between 1 and . Then so . Also, is within of 1 so 4 is within of , and is between and 4.5: .
Let be between 1 and . Then so . Also, is within of 1 so 2 is within of , and is between and .
(iii) The two inequalities in bold print provide the contradiction we were hoping to find. There is no value that simultaneously satisfies and , so we can conclude that our assumption was false and that does not have a limit as .
Practice 6: Use the definition to prove that does not exist (Fig. 15).
Two Limit Theorems
The theorems and their proofs are included here so you can see how such proofs proceed - you have already used these theorems to evaluate limits of functions. There are rigorous proofs of all of the other limit properties, but they are somewhat more complicated than the proofs given here.
Proof: Case : The Theorem is true but not very interesting: .
Case : Since , then, by the definition, for every there is a so that whenever For any , we know and pick a value of that satisfies whenever . When
is within of ") then is within of L") so (multiplying each side by ) and is within of
Proof: Assume that and . Then, given any , we know and that there are deltas for and and , so that
if , then ("if is within of , then is within of ", and
if , then ("if is within of , then is within of ").
Let be the smaller of and If , then and so
Practice Problem Answers
Practice 1: (a) so and " within unit of ".
(c) so and : "x within units of ".
Practice 2: "within 1 unit of 3": If , then which extends from 5 units to the left of 9 to 7 units to right of 9. Using the smaller of these two distances from 9, "If is within 5 units of 9, then is within unit of ".
"within units of ": If , then which extends from units to the left of 9 to units to the right of 9. "If is within units of 9, then is wqithin units of .
Practice 3: See Fig. 22.
Practice 4: See Fig. 23.
We have shown that "for any , there is a (namely " so that the rest of the definition is satisfied.
Practice 6: This is a much more sophisticated (= harder) problem.
Using "proof by contradiction" as outlined in the solution to Example 6.
(i) Assume that the limit exists: for some value for . Let . (The definition says "for every ε" so we can pick this value. For this limit, the definition fails for every ) Then, since we are assuming that the limit exists, there is a so that if is within of 0 then is within of L.
(ii) (See Fig. 24) Let be between and and also require that . Then so . Since is within of is within of , so L is greater than .
Let be between 0 and and also require that . Then so . Since is within of is
(iii) The two inequalities in bold print provide the contradiction we hoping to find, There is no value that satisfies
so we can conclude that our assumption was false and that does not have a limit as .