5. My Three Sums



Answer:
The partially completed program is below.
The last blank could also have been filled by
    count++ ;






My Three Sums





    
        

        

        

            
                
import  java.util.Scanner;

// User enters a value N
// Add up odd integers,  
// even  integers, and all integers 1 to N
//
public class AddUpIntegers
{
  public static void main (String[] args ) 
  {
    Scanner scan = new Scanner( System.in );
    int N, sumAll = 0, sumEven = 0, sumOdd = 0;

    System.out.print( "Enter limit value: " );
    N = scan.nextInt();

    int count = 1 ;
    while (  count <= N )    
    {
      System.out.println("count: " + count );   // temporary statement for testing
      (more statements  go here )

      count = count + 1 ;
    }

    System.out.print  ( "Sum of all : " + sumAll  );
    System.out.print  ( "\tSum of even: " + sumEven );
    System.out.println( "\tSum of odd : " + sumOdd  );
  }
}

            		
        

    


The program, given above, can be compiled and run. As soon as you have a program that can be run, do so. Correct syntax errors (if any) and look for bugs. Insert some temporary println statements to help in the bug search. (Or use a debugger.)
The loop counts through the integers we are interested in, but it does not yet do anything with them. This is what we want to happen:
      • Each integer added to sumAll.
      • Each odd integer added to sumOdd.
      • Each even integer added to sumEven.






Question 5:
How do you decide which sum (sumOdd or sumEven) to add an integer to?