## Try It Now

Work these exercises to see how well you understand this material.

### Exercises

- A box contains 10 white and 10 black marbles. Construct a sample space for the experiment of randomly drawing out, with replacement, two marbles in succession and noting the color each time. (To draw "with replacement" means that the first marble is put back before the second marble is drawn.)
- A box contains 8 red, 8 yellow, and 8 green marbles. Construct a sample space for the experiment of randomly drawing out, with replacement, two marbles in succession and noting the color each time.
- In the situation of Exercise 1, list the outcomes that comprise each of the following events.
- At least one marble of each color is drawn.
- No white marble is drawn.

- In the situation of Exercise 3, list the outcomes that comprise each of the following events.
- No yellow marble is drawn.
- The two marbles drawn have the same color.
- At least one marble of each color is drawn.

- Assuming that each outcome is equally likely, find the probability of each event in Exercise 5.
- Assuming that each outcome is equally likely, find the probability of each event in Exercise 7.
- A sample space is
*S*= {a, b, c, d, e}. Identify two events as*U*= {a, b, d} and*V*= {b, c, d}. Suppose*P*(a) and*P*(b) are each 0.2 and*P*(c) and*P*(d) are each 0.1.- Determine what
*P*(e) must be. - Find
*P*(U). - Find
*P*(V).

- Determine what
- A sample space is
*S*= {m, n, q, r, s}. Identify two events as*U*= {m, q, s} and*V*= {n, q, r}. The probabilities of some of the outcomes are given by the following table:- Determine what
*P*(q) must be. - Find
*P*(U). - Find
*P*(V).

- Determine what
- The sample space that describes all three-child families according to the genders of the children with respect to birth order was constructed in Note 3.9 "Example 4". Identify the outcomes that comprise each of the following events in the experiment of selecting a three-child family at random.
- At least one child is a girl.
- At most one child is a girl.
- All of the children are girls.
- Exactly two of the children are girls.
- The first born is a girl.

- Assuming that the outcomes are equally likely, find the probability of each event in Exercise 17.
- The following two-way contingency table gives the breakdown of the population in a particular locale according to age and tobacco usage:

Age Tobacco Use Smoker Non-smoker Under 30 0.05 0.20 Over 30 0.20 0.55

A person is selected at random. Find the probability of each of the following events.- The person is a smoker.
- The person is under 30.
- The person is a smoker who is under 30.

- The following two-way contingency table gives the breakdown of the population of married or previously married women beyond child-bearing age in a particular locale according to age at first marriage and number of children:

A woman is selected at random. Find the probability of each of the following events.

Age Number of Children 0 1 or 2 3 or More Under 20 0.02 0.14 0.08 20–29 0.07 0.37 0.11 30 and above 0.10 0.10 0.01

- The woman was in her twenties at her first marriage.
- The woman was 20 or older at her first marriage.
- The woman had no children.
- The woman was in her twenties at her first marriage and had at least three children.

Source: Saylor Academy, https://saylordotorg.github.io/text_introductory-statistics/index.html

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