Practice Problems

Work through the odd-numbered problems 1-61. Once you have completed the problem set, check your answers.

Practice Problems

Answers

1. 2^{2}+3^{2}+4^{2}=29

3. (1+1)^{2}+(1+2)^{2}+(1+3)^{2}=29

5. \cos (0)+\cos (\pi)+\cos (2 \pi)+\cos (3 \pi)+\cos (4 \pi)+\cos (5 \pi)=1+(-1)+1+(-1)+1+(-1)=0


7. \sum_{\mathrm{k}=3}^{94} \mathrm{k}

9. \sum_{k=3}^{12} k^{2}

11. \sum_{k=1}^{7} k \cdot 2^{k}


13. (a)  (1+2)+(2+2)+(3+2)=3+4+5=12           (b) (1+2+3)+(2+2+2)=12

15. (a)  5 \cdot 1+5 \cdot 2+5 \cdot 3=5+10+15=30                        (b)  5 \cdot(1+2+3)=5 \cdot 6=30


17. (a)  1^{2}+2^{2}+3^{2}=1+4+9=14                                     (b)  (1+2+3)^{2}=6^{2}=36


19. f(0)+f(1)+f(2)+f(3)=0^{2}+1^{2}+2^{2}+3^{2}=14

21. 2 \cdot f(0)+2 \cdot f(1)+2 \cdot f(2)+2 \cdot f(3)=2 \cdot 0+2 \cdot 1+2 \cdot 4+2 \cdot 9=28

23. g(1)+g(2)+g(3)=3+6+9=18

25. g^{2}(1)+g^{2}(2)+g^{2}(3)=3^{2}+6^{2}+9^{2}=126

27. \mathrm{h}(2)+\mathrm{h}(3)+\mathrm{h}(4)=\frac{2}{2}+\frac{2}{3}+\frac{2}{4}=\frac{13}{6}

29. \mathrm{f}(1) \mathrm{h}(1)+\mathrm{f}(2) \mathrm{h}(2)+\mathrm{f}(3) \mathrm{h}(3)=(1)(2)+(4)(1)+(9)(2 / 3)=12


31. \left(1^{2}-0^{2}\right)+\left(2^{2}-1^{2}\right)+\left(3^{2}-2^{2}\right)+\left(4^{2}-3^{2}\right)+\ldots+\left(7^{2}-6^{2}\right)=7^{2}-0^{2}=49

33. \left(\frac{1}{1}-\frac{1}{2}\right)+\left(\frac{1}{2}-\frac{1}{3}\right)+\left(\frac{1}{3}-\frac{1}{4}\right)+\left(\frac{1}{4}-\frac{1}{5}\right)+\left(\frac{1}{5}-\frac{1}{6}\right)=1-\frac{1}{6}=\frac{5}{6}

35. (\sqrt{1}-\sqrt{0})+(\sqrt{2}-\sqrt{1})+(\sqrt{3}-\sqrt{2})+\ldots+(\sqrt{9}-\sqrt{8})=\sqrt{9}-\sqrt{0}=3


37. (i)  [2,3],[3,4.5],[4.5,6],[6,7]                   (ii)  1,1.5,1.5,1              (iii)  \text {mesh }=1.5             (iv)  1+1.5+1.5+1=5

39. (i)  [-3,-1],[-1,0],[0,1.5],[1.5,2]         (ii)  2,1,1.5,0.5             (iii)  \text {mesh }=2                 (iv)  2+1+1.5+0.5=5


41. (i)  [3,3.8],[3.8,4.5],[4.5,5.2],[5.2,7]      (ii)  0.8,0.7,0.7,1.8       (iii)  \text { mesh }=1.8             (iv)  0.8+0.7+0.7+1.8=4


43. \begin{aligned} &\Delta x_{1}+\Delta x_{2}+\Delta x_{3}+\ldots+\Delta x_{n}=\left(x_{1}-x_{0}\right)+\left(x_{2}-x_{1}\right)+\left(x_{3}-x_{2}\right)+\ldots+\left(x_{n}-\right. \\ &\left.x_{n-1}\right)=x_{n}-x_{0} \end{aligned}


45.
(a)  f(0)(1)+f(1)(0.5)+f(2)(0.5)=(4)(1)+(3)(0.5)+(0)(0.5)=5.5
(b)  \mathrm{f}(1)(1)+\mathrm{f}(1.5)(0.5)+\mathrm{f}(1.5)(0.5)=(3)(1)+(1.75)(0.5)+(1.75)(0.5)=4.75

47. a. (i) and (ii) See the graph
(iii)  \mathrm{f}(0)=0, \mathrm{f}(\pi / 4) \approx 0.707, \mathrm{f}(\pi / 2)=1
(iv)  (\pi / 4)(0)+(\pi / 4)(0.707)+(\pi / 2)(1) \approx 2.13


49.

(a)  (2)(1)+(5)(2)+(17)(1) \leq \mathrm{RS} \leq(5)(1)+(17)(2)+(26)(1) \text { so } 29 \leq \mathrm{RS} \leq 65
(b)  (2)(1)+(5)(1)+(10)(1)+(17)(1) \leq \mathrm{RS} \leq(5)(1)+(10)(1)+(17)(1)+(26)(1) \text { so } 34 \leq
    \mathrm{RS} \leq 58
(c)  (2)(0.5)+(3.25)(0.5)+(5)(1)+(10)(1)+(17)(1) \leq \mathrm{RS} \leq(3.25)(0.5)+(5)(0.5)+(10)(1)+(17)(1)+(26)(1) so 34.625 \leq \mathrm{RS} \leq 57.125


51.
(a)  (0)(\pi / 2)+(0)(\pi / 2) \leq \mathrm{RS} \leq(1)(\pi / 2)+(1)(\pi / 2) \text { so } 0 \leq \mathrm{RS} \leq \pi
(b)  (0)(\pi / 4)+(0.707)(\pi / 4)+(0)(\pi / 2) \leq \mathrm{RS} \leq(0.707)(\pi / 4)+(1)(\pi / 4)+(1)(\pi
    / 2) \text { so } 0.56 \leq \mathrm{RS} \leq 2.91
(c)  (0)(\pi / 4)+(0.707)(\pi /)+(0.707)(\pi / 4)+(0)(\pi / 4) \leq \mathrm{RS} \leq(0.707)(\pi / 4)+(1)(\pi / 4)+(1)(\pi / 4)+(0.707)(\pi / 4) so 1.11 \leq \mathrm{RS} \leq
    2.68


53. (a)  17.402-7.362 \mid=0.04                      (b)  |7.390-7.372|=0.018


55. \text { I error } \mathrm{I} \leq\left(\text { base) }(\text { height })=\frac{4-2}{50}(65-9)=\frac{2}{50}(56)=\frac{112}{50}=2.24\right.


57. (a)  \frac{100(101)}{2}=5050                                       (b)  \begin{aligned}
&1+2+3+\ldots+100 \\
&100+99+98+\ldots+1 \\ \hline &101+101+101+\ldots+101=100(101)=10100 . \quad \frac{1}{2}(10100)=5050
\end{aligned}     


59. 10+11+12+\ldots+20=(1+2+3+\ldots+20)-(1+2+3+\ldots+9)=\frac{20(21)}{2}-\frac{9(10)}{2}=210-45=165


61. \sum_{k=1}^{10}\left(k^{3}+k\right)=\sum_{k=1}^{10} \mathrm{k}^{3}+\sum_{k=1}^{10} \mathrm{k}=\left(\frac{10(11)}{2}\right)^{2}+\frac{10(11)}{2}=(55)^{2}+55=3080