Energy and the Simple Harmonic Oscillator

In terms of energy, damped oscillations cannot maintain a constant balance of kinetic and potential energy because some of the mechanical energy is drained away in the form of thermal energy. This eventually causes the mechanical motion of the oscillator to return to equilibrium and stay there. At that point, all the energy of the oscillation has been converted to microscopic, invisible motion at the molecular level in the surrounding air or the oscillator itself.

To study the energy of a simple harmonic oscillator, we first consider all the forms of energy it can have We know from Hooke’s Law: Stress and Strain Revisited that the energy stored in the deformation of a simple harmonic oscillator is a form of potential energy given by:

PE_{el}=\frac{1}{2}kx^{2} [equation 16.33]

Because a simple harmonic oscillator has no dissipative forces, the other important form of energy is kinetic energy KE. Conservation of energy for these two forms is:

KE+PE_{el}=constant [equation 16.34]

or

\frac{1}{2}mv^{2}+\frac{1}{2}kx^{2}=constant [equation 16.35]

This statement of conservation of energy is valid for all simple harmonic oscillators, including ones where the gravitational force plays a role

Namely, for a simple pendulum we replace the velocity with v=L\omega, the spring constant with k=mg/L, and the displacement term with x=L\theta . Thus

\frac{1}{2}mL^{2}\omega^{2}+\frac{1}{2}mgL\theta ^{2}=constant [equation 16.36]

In the case of undamped simple harmonic motion, the energy oscillates back and forth between kinetic and potential, going completely from one to the other as the system oscillates. So for the simple example of an object on a frictionless surface attached to a spring, as shown again in Figure 16.16, the motion starts with all of the energy stored in the spring.

As the object starts to move, the elastic potential energy is converted to kinetic energy, becoming entirely kinetic energy at the equilibrium position. It is then converted back into elastic potential energy by the spring, the velocity becomes zero when the kinetic energy is completely converted, and so on. This concept provides extra insight here and in later applications of simple harmonic motion, such as alternating current circuits.

Five diagrams of springs on a frictionless surface to illustrate simple harmonic motion.

Figure 16.16 The transformation of energy in simple harmonic motion is illustrated for an object attached to a spring on a frictionless surface.


The conservation of energy principle can be used to derive an expression for velocity v. If we start our simple harmonic motion with zero velocity and maximum displacement (x=X), then the total energy is

\frac{1}{2}kX^{2} [equation 16.37]

This total energy is constant and is shifted back and forth between kinetic energy and potential energy, at most times being shared by each. The conservation of energy for this system in equation form is thus:

\frac{1}{2}mv^{2}+\frac{1}{2}kx^{2}=\frac{1}{2}kX^{2} [equation 16.38]

Solving this equation for v:

v=\pm \sqrt{\frac{k}{m}(X^{2}-x^{2})} [equation 16.39]

Manipulating this expression algebraically gives:

v=\pm \sqrt{\frac{k}{m}}X\sqrt{1-\frac{x^{2}}{X^{2}}} [equation 16.40]

and so

v=\pm v_{max}\sqrt{1-\frac{x^{2}}{X^{2}}} [equation 16.41]

where

v_{max}=\sqrt{\frac{k}{m}}X [equation 16.42]

From this expression, we see that the velocity is a maximum (v_{max}) at x=0, as stated earlier in v(t)=-v_{max}\: sin\: \frac{2\pi t}{T}. Notice that the maximum velocity depends on three factors. Maximum velocity is directly proportional to amplitude. As you might guess, the greater the maximum displacement the greater the maximum velocity. Maximum velocity is also greater for stiffer systems, because they exert greater force for the same displacement.

This observation is seen in the expression for 𝑣max; it is proportional to the square root of the force constant 𝑘. Finally, the maximum velocity is smaller for objects that have larger masses, because the maximum velocity is inversely proportional to the square root of 𝑚. For a given force, objects that have large masses accelerate more slowly.

A similar calculation for the simple pendulum produces a similar result, namely:

\omega _{max}=\sqrt{\frac{g}{L}}\theta _{max} [equation 16.43]

Example 16.6 Determine the Maximum Speed of an Oscillating System: A Bumpy Road

Suppose that a car is 900 kg and has a suspension system that has a force constant k=6.53\times 10^{4}\: N/m. The car hits a bump and bounces with an amplitude of 0.100 m. What is its maximum vertical velocity if you assume no damping occurs?


Strategy

We can use the expression for v_{max} given in v_{max}=\sqrt{\frac{k}{m}}X to determine the maximum vertical velocity. The variables m and k are given in the problem statement, and the maximum displacement X is 0.100 m.


Solution

1. Identify known.

2. Substitute known values into v_{max}=\sqrt{\frac{k}{m}}X:

v_{max}=\sqrt{\frac{6.53\times 10^{4}\: N/m}{900\: kg}}(0.100\: m) [equation 16.44]

Calculate to find v_{max}=0.853\: m/s


Discussion

This answer seems reasonable for a bouncing car. There are other ways to use conservation of energy to find v_{max}. We could use it directly, as was done in the example featured in Hooke’s Law: Stress and Strain Revisited.

The small vertical displacement y of an oscillating simple pendulum, starting from its equilibrium position, is given as

y(t)=a\: sin\: \omega t [equation 16.45]

where a is the amplitude, \omega is the angular velocity and t is the time taken. Substituting \omega =\frac{2\pi }{T}, we have

y(t)=a\: sin\: (\frac{2\pi t}{T}) [equation 16.46]

Thus, the displacement of pendulum is a function of time as shown above.

Also the velocity of the pendulum is given by

v(t)=\frac{2a\pi }{T}cos\: (\frac{2\pi t}{T}) [equation 16.47]

so the motion of the pendulum is a function of time.



Source: Rice University, https://openstax.org/books/college-physics/pages/16-5-energy-and-the-simple-harmonic-oscillator
Creative Commons License This work is licensed under a Creative Commons Attribution 4.0 License.

Last modified: Tuesday, August 31, 2021, 9:12 AM