Different Ways to Create and Manipulate an Array

In JavaScript, arrays can be created in various ways. This section provides examples of using Array literal notation and constructors with single and multiple parameters. Another way to create an array is by using the split() method to convert a string into an ordered list. This method can be particularly useful when taking input from users as strings. This section also provides some examples of common array operations in JavaScript.


Create an array

This example shows three ways to create new array: first using array literal notation, then using the Array() constructor, and finally using String.prototype.split() to build the array from a string.

// 'fruits' array created using array literal notation.
const fruits = ["Apple", "Banana"];
console.log(fruits.length);
// 2

// 'fruits2' array created using the Array() constructor.
const fruits2 = new Array("Apple", "Banana");
console.log(fruits2.length);
// 2

// 'fruits3' array created using String.prototype.split().
const fruits3 = "Apple, Banana".split(", ");
console.log(fruits3.length);
// 2


Create a string from an array

This example uses the join() method to create a string from the fruits array.

const fruits = ["Apple", "Banana"];
const fruitsString = fruits.join(", ");
console.log(fruitsString);
// "Apple, Banana"


Access an array item by its index

This example shows how to access items in the fruits array by specifying the index number of their position in the array.

const fruits = ["Apple", "Banana"];

// The index of an array's first element is always 0.
fruits[0]; // Apple

// The index of an array's second element is always 1.
fruits[1]; // Banana

// The index of an array's last element is always one
// less than the length of the array.
fruits[fruits.length - 1]; // Banana

// Using an index number larger than the array's length
// returns 'undefined'.
fruits[99]; // undefined


Find the index of an item in an array

This example uses the indexOf() method to find the position (index) of the string "Banana" in the fruits array.

const fruits = ["Apple", "Banana"];
console.log(fruits.indexOf("Banana"));
// 1


Check if an array contains a certain item

This example shows two ways to check if the fruits array contains "Banana" and "Cherry": first with the includes() method, and then with the indexOf() method to test for an index value that's not -1.

const fruits = ["Apple", "Banana"];

fruits.includes("Banana"); // true
fruits.includes("Cherry"); // false

// If indexOf() doesn't return -1, the array contains the given item.
fruits.indexOf("Banana") !== -1; // true
fruits.indexOf("Cherry") !== -1; // false


Append an item to an array

This example uses the push() method to append a new string to the fruits array.

const fruits = ["Apple", "Banana"];
const newLength = fruits.push("Orange");
console.log(fruits);
// ["Apple", "Banana", "Orange"]
console.log(newLength);
// 3


Remove the last item from an array

This example uses the pop() method to remove the last item from the fruits array.

const fruits = ["Apple", "Banana", "Orange"];
const removedItem = fruits.pop();
console.log(fruits);
// ["Apple", "Banana"]
console.log(removedItem);
// Orange

Note: pop() can only be used to remove the last item from an array. To remove multiple items from the end of an array, see the next example.


Remove multiple items from the end of an array

This example uses the splice() method to remove the last 3 items from the fruits array.

const fruits = ["Apple", "Banana", "Strawberry", "Mango", "Cherry"];
const start = -3;
const removedItems = fruits.splice(start);
console.log(fruits);
// ["Apple", "Banana"]
console.log(removedItems);
// ["Strawberry", "Mango", "Cherry"]


Truncate an array down to just its first N items

This example uses the splice() method to truncate the fruits array down to just its first 2 items.

const fruits = ["Apple", "Banana", "Strawberry", "Mango", "Cherry"];
const start = 2;
const removedItems = fruits.splice(start);
console.log(fruits);
// ["Apple", "Banana"]
console.log(removedItems);
// ["Strawberry", "Mango", "Cherry"]


Remove the first item from an array

This example uses the shift() method to remove the first item from the fruits array.

const fruits = ["Apple", "Banana"];
const removedItem = fruits.shift();
console.log(fruits);
// ["Banana"]
console.log(removedItem);
// Apple

Note: shift() can only be used to remove the first item from an array. To remove multiple items from the beginning of an array, see the next example.


Remove multiple items from the beginning of an array

This example uses the splice() method to remove the first 3 items from the fruits array.

const fruits = ["Apple", "Strawberry", "Cherry", "Banana", "Mango"];
const start = 0;
const deleteCount = 3;
const removedItems = fruits.splice(start, deleteCount);
console.log(fruits);
// ["Banana", "Mango"]
console.log(removedItems);
// ["Apple", "Strawberry", "Cherry"]


Add a new first item to an array

This example uses the unshift() method to add, at index 0, a new item to the fruits array - making it the new first item in the array.

const fruits = ["Banana", "Mango"];
const newLength = fruits.unshift("Strawberry");
console.log(fruits);
// ["Strawberry", "Banana", "Mango"]
console.log(newLength);
// 3


Remove a single item by index

This example uses the splice() method to remove the string "Banana" from the fruits array - by specifying the index position of "Banana".

const fruits = ["Strawberry", "Banana", "Mango"];
const start = fruits.indexOf("Banana");
const deleteCount = 1;
const removedItems = fruits.splice(start, deleteCount);
console.log(fruits);
// ["Strawberry", "Mango"]
console.log(removedItems);
// ["Banana"]


Remove multiple items by index

This example uses the splice() method to remove the strings "Banana" and "Strawberry" from the fruits array - by specifying the index position of "Banana", along with a count of the number of total items to remove.

const fruits = ["Apple", "Banana", "Strawberry", "Mango"];
const start = 1;
const deleteCount = 2;
const removedItems = fruits.splice(start, deleteCount);
console.log(fruits);
// ["Apple", "Mango"]
console.log(removedItems);
// ["Banana", "Strawberry"]


Replace multiple items in an array

This example uses the splice() method to replace the last 2 items in the fruits array with new items.

const fruits = ["Apple", "Banana", "Strawberry"];
const start = -2;
const deleteCount = 2;
const removedItems = fruits.splice(start, deleteCount, "Mango", "Cherry");
console.log(fruits);
// ["Apple", "Mango", "Cherry"]
console.log(removedItems);
// ["Banana", "Strawberry"]


Iterate over an array

This example uses a for...of loop to iterate over the fruits array, logging each item to the console.

const fruits = ["Apple", "Mango", "Cherry"];
for (const fruit of fruits) {
  console.log(fruit);
}
// Apple
// Mango
// Cherry

But for...of is just one of many ways to iterate over any array; for more ways, see Loops and iteration, and see the documentation for the every(), filter(), flatMap(), map(), reduce(), and reduceRight() methods - and see the next example, which uses the forEach() method.


Call a function on each element in an array

This example uses the forEach() method to call a function on each element in the fruits array; the function causes each item to be logged to the console, along with the item's index number.

const fruits = ["Apple", "Mango", "Cherry"];
fruits.forEach((item, index, array) => {
  console.log(item, index);
});
// Apple 0
// Mango 1
// Cherry 2


Merge multiple arrays together

This example uses the concat() method to merge the fruits array with a moreFruits array, to produce a new combinedFruits array. Notice that fruits and moreFruits remain unchanged.

const fruits = ["Apple", "Banana", "Strawberry"];
const moreFruits = ["Mango", "Cherry"];
const combinedFruits = fruits.concat(moreFruits);
console.log(combinedFruits);
// ["Apple", "Banana", "Strawberry", "Mango", "Cherry"]

// The 'fruits' array remains unchanged.
console.log(fruits);
// ["Apple", "Banana", "Strawberry"]

// The 'moreFruits' array also remains unchanged.
console.log(moreFruits);
// ["Mango", "Cherry"]


Copy an array

This example shows three ways to create a new array from the existing fruits array: first by using spread syntax, then by using the from() method, and then by using the slice() method.

const fruits = ["Strawberry", "Mango"];

// Create a copy using spread syntax.
const fruitsCopy = [...fruits];
// ["Strawberry", "Mango"]

// Create a copy using the from() method.
const fruitsCopy2 = Array.from(fruits);
// ["Strawberry", "Mango"]

// Create a copy using the slice() method.
const fruitsCopy3 = fruits.slice();
// ["Strawberry", "Mango"]

All built-in array-copy operations (spread syntax, Array.from(), Array.prototype.slice(), and Array.prototype.concat()) create shallow copies. If you instead want a deep copy of an array, you can use JSON.stringify() to convert the array to a JSON string, and then JSON.parse() to convert the string back into a new array that's completely independent from the original array.

const fruitsDeepCopy = JSON.parse(JSON.stringify(fruits));

You can also create deep copies using the structuredClone() method, which has the advantage of allowing transferable objects in the source to be transferred to the new copy, rather than just cloned.

Finally, it's important to understand that assigning an existing array to a new variable doesn't create a copy of either the array or its elements. Instead the new variable is just a reference, or alias, to the original array; that is, the original array's name and the new variable name are just two names for the exact same object (and so will always evaluate as strictly equivalent). Therefore, if you make any changes at all either to the value of the original array or to the value of the new variable, the other will change, too:

const fruits = ["Strawberry", "Mango"];
const fruitsAlias = fruits;
// 'fruits' and 'fruitsAlias' are the same object, strictly equivalent.
fruits === fruitsAlias; // true
// Any changes to the 'fruits' array change 'fruitsAlias' too.
fruits.unshift("Apple", "Banana");
console.log(fruits);
// ['Apple', 'Banana', 'Strawberry', 'Mango']
console.log(fruitsAlias);
// ['Apple', 'Banana', 'Strawberry', 'Mango']


Grouping the elements of an array

The Array.prototype.group() methods can be used to group the elements of an array, using a test function that returns a string indicating the group of the current element.

Here we have a simple inventory array that contains "food" objects that have a name and a type.

const inventory = [
  { name: "asparagus", type: "vegetables" },
  { name: "bananas", type: "fruit" },
  { name: "goat", type: "meat" },
  { name: "cherries", type: "fruit" },
  { name: "fish", type: "meat" },
];

To use group(), you supply a callback function that is called with the current element, and optionally the current index and array, and returns a string indicating the group of the element.

The code below uses an arrow function to return the type of each array element (this uses object destructuring syntax for function arguments to unpack the type element from the passed object). The result is an object that has properties named after the unique strings returned by the callback. Each property is assigned an array containing the elements in the group.

const result = inventory.group(({ type }) => type);
console.log(result.vegetables);
// { name: "asparagus", type: "vegetables" }

Note that the returned object references the same elements as the original array (not deep copies). Changing the internal structure of these elements will be reflected in both the original array and the returned object.

If you can't use a string as the key, for example, if the information to group is associated with an object that might change, then you can instead use Array.prototype.groupToMap(). This is very similar to group except that it groups the elements of the array into a Map that can use an arbitrary value (object or primitive) as a key.


Creating a two-dimensional array

The following creates a chessboard as a two-dimensional array of strings. The first move is made by copying the 'p' in board[6][4] to board[4][4]. The old position at [6][4] is made blank.

const board = [
  ["R", "N", "B", "Q", "K", "B", "N", "R"],
  ["P", "P", "P", "P", "P", "P", "P", "P"],
  [" ", " ", " ", " ", " ", " ", " ", " "],
  [" ", " ", " ", " ", " ", " ", " ", " "],
  [" ", " ", " ", " ", " ", " ", " ", " "],
  [" ", " ", " ", " ", " ", " ", " ", " "],
  ["p", "p", "p", "p", "p", "p", "p", "p"],
  ["r", "n", "b", "q", "k", "b", "n", "r"],
];

console.log(`${board.join("\n")}\n\n`);

// Move King's Pawn forward 2
board[4][4] = board[6][4];
board[6][4] = " ";
console.log(board.join("\n"));

Here is the output:

R,N,B,Q,K,B,N,R
P,P,P,P,P,P,P,P
 , , , , , , ,
 , , , , , , ,
 , , , , , , ,
 , , , , , , ,
p,p,p,p,p,p,p,p
r,n,b,q,k,b,n,r

R,N,B,Q,K,B,N,R
P,P,P,P,P,P,P,P
 , , , , , , ,
 , , , , , , ,
 , , , ,p, , ,
 , , , , , , ,
p,p,p,p, ,p,p,p
r,n,b,q,k,b,n,r


Using an array to tabulate a set of values

const values = [];
for (let x = 0; x < 10; x++) {
  values.push([2 ** x, 2 * x ** 2]);
}
console.table(values);

Results in

// The first column is the index
0  1    0
1  2    2
2  4    8
3  8    18
4  16   32
5  32   50
6  64   72
7  128  98
8  256  128
9  512  162


Creating an array using the result of a match

The result of a match between a RegExp and a string can create a JavaScript array that has properties and elements which provide information about the match. Such an array is returned by RegExp.prototype.exec() and String.prototype.match().

For example:

// Match one d followed by one or more b's followed by one d
// Remember matched b's and the following d
// Ignore case

const myRe = /d(b+)(d)/i;
const execResult = myRe.exec("cdbBdbsbz");

console.log(execResult.input); // 'cdbBdbsbz'
console.log(execResult.index); // 1
console.log(execResult); // [ "dbBd", "bB", "d" ]


Source: Mozilla, https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array#constructor
Creative Commons License This work is licensed under a Creative Commons Attribution-ShareAlike 2.5 License.

Last modified: Thursday, July 20, 2023, 5:38 PM