Complexity Assessment of Assembly Supply Chains from the Sustainability Viewpoint

Testing and Comparison of ASC Complexity Indicators

Testing of C#5

C#5 is proposing the following statement:
If i, j, and k are constant and the number of echelons is increasing, then the complexity of ASC(i,j,k) ˂ ASC(i,j,k) with an increasing number of echelons.

Let us test ASC1(3,4,3) and ASC2(3,4,3), shown in Figure 7. While in Figure 7a, ASC1 consists of three machines and operations (i = k = 3), the number of parts equals four (j = 4), and the number of echelons equals two, in Figure 7b, ASC2 contains three machines (i = 3), four operations (k = 4), the number of parts equals four (j = 4), and the number of echelons equals three.

Applying Equation (4), according to complexity indicator Ivd, we obtained the following results for Ivd1 and Ivd2:

Ivd1 = 3 × log23 + 3 × log23 + 2 × log22 = 11.51 bits
Ivd2 = 3 × log23 + 3 × log23 + 2 × log22 = 11.51 bits

Applying Equation (5), according to complexity indicator PCI, we obtained the following results for PCI1 and PCI2:

PCI1 = −(0.5 × log20.5 + 0.5 × log20.5 + 0.5 × log20.5 + 0.5 × log20.5) = 4 bits
PCI2 = −(0.33 × log20.33 + 0.33 × log20.33 + 0.33 × log20.33 + 0.33 × log20.33 + 0.33 × log20.33 + 0.33 × log20.33 + 0.5 × log20.5 + 0.5 × log20.5 + 1 × log21) = 4.17 bits

Applying Equation (9), according to complexity indicator SDC, we obtained the following results for SDC1 and SDC2:

SDC1 = 4 × ln4 + 2 × ln2 + 2 × ln2 = 8.32 nats
SDC2 = 4 × ln4 + 3 × ln3 + 2 × ln2 = 10.23 nats

Applying Equation (10), according to complexity indicator MFC, we obtained the following results for MFC1 and MFC2:

MFC1 = 0 × 3 + 1 × 7 + 1 × 6 = 13
MFC2 = 0 × 4 + 1 × 7 + 1 × 6 = 13

According to the three complexity indicators PCI, SDC, and MFC, it was proved that the complexity of ASC1 ˂ the complexity of ASC2, then ASC(i,j,k) ˂ ASC(i,j,k) with an increasing number of echelons.