Basic C++ Exercises
Solutions
Exercise 1 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { cout << "\n\n Print a welcome text in a separate line :\n"; cout << "----------------------------------------------\n"; cout << " Welcome to \n" ; cout << " w3resource.com "<<endl ; }
Sample Output:
Print a welcome text in a separate line : ---------------------------------------------- Welcome to w3resource.com
Exercise 2 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { cout << "\n\n Print the sum of two numbers :\n"; cout << "-----------------------------------\n"; cout << " The sum of 29 and 30 is : "<< 29+30 <<"\n\n" ; }
Sample Output:
Print the sum of two numbers : ----------------------------------- The sum of 29 and 30 is : 59
Exercise 3 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { cout << "\n\n Find Size of fundamental data types :\n"; cout << "------------------------------------------\n"; cout << " The sizeof(char) is : " << sizeof(char) << " bytes \n" ; cout << " The sizeof(short) is : " << sizeof(short) << " bytes \n" ; cout << " The sizeof(int) is : " << sizeof(int) << " bytes \n" ; cout << " The sizeof(long) is : " << sizeof(long) << " bytes \n" ; cout << " The sizeof(long long) is : " << sizeof(long long) << " bytes \n"; cout << " The sizeof(float) is : " << sizeof(float) << " bytes \n" ; cout << " The sizeof(double) is : " << sizeof(double) << " bytes \n"; cout << " The sizeof(long double) is : " << sizeof(long double) << " bytes \n"; cout << " The sizeof(bool) is : " << sizeof(bool) << " bytes \n\n"; return 0; }
Sample Output:
Find Size of fundamental data types : ------------------------------------------ The sizeof(char) is : 1 bytes The sizeof(short) is : 2 bytes The sizeof(int) is : 4 bytes The sizeof(long) is : 8 bytes The sizeof(long long) is : 8 bytes The sizeof(float) is : 4 bytes The sizeof(double) is : 8 bytes The sizeof(long double) is : 16 bytes The sizeof(bool) is : 1 bytes
Exercise 4 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { cout << "\n\n Print the sum of two numbers :\n"; cout << "-----------------------------------\n"; int a; int b; int sum; a=29; b=30; sum=a+b; cout << " The sum of "<< a << " and "<<b <<" is : "<< sum <<"\n\n" ; }
Sample Output:
Print the sum of two numbers : ----------------------------------- The sum of 29 and 30 is : 59
Exercise 5 Solution
Sample C++ Code:
#include <iostream> #include <climits> // integer limits in header file using namespace std; int main() { cout << "\n\n Check the upper and lower limits of integer :\n"; cout << "--------------------------------------------------\n"; cout << " The maximum limit of int data type : " << INT_MAX << endl; cout << " The minimum limit of int data type : " << INT_MIN << endl; cout << " The maximum limit of unsigned int data type : " << UINT_MAX << endl; cout << " The maximum limit of long long data type : " << LLONG_MAX << endl; cout << " The minimum limit of long long data type : " << LLONG_MIN << endl; cout << " The maximum limit of unsigned long long data type : " << ULLONG_MAX << endl; cout << " The Bits contain in char data type : " << CHAR_BIT << endl; cout << " The maximum limit of char data type : " << CHAR_MAX << endl; cout << " The minimum limit of char data type : " << CHAR_MIN << endl; cout << " The maximum limit of signed char data type : " << SCHAR_MAX << endl; cout << " The minimum limit of signed char data type : " << SCHAR_MIN << endl; cout << " The maximum limit of unsigned char data type : " << UCHAR_MAX << endl; cout << " The minimum limit of short data type : " << SHRT_MIN << endl; cout << " The maximum limit of short data type : " << SHRT_MAX << endl; cout << " The maximum limit of unsigned short data type : " << USHRT_MAX << endl; cout << endl; return 0; }
Sample Output:
Check the upper and lower limits of integer : -------------------------------------------------- The maximum limit of int data type : 2147483647 The minimum limit of int data type : -2147483648 The maximum limit of unsigned int data type : 4294967295 The maximum limit of long long data type : 9223372036854775807 The minimum limit of long long data type : -9223372036854775808 The maximum limit of unsigned long long data type : 18446744073709551615 The Bits contain in char data type : 8 The maximum limit of char data type : 127 The minimum limit of char data type : -128 The maximum limit of signed char data type : 127 The minimum limit of signed char data type : -128 The maximum limit of unsigned char data type : 255 The minimum limit of short data type : -32768 The maximum limit of short data type : 32767 The maximum limit of unsigned short data type : 65535
Exercise 6 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { cout << "\n\n Check whether the primitive values crossing the limits or not :\n"; cout << "--------------------------------------------------------------------\n"; char gender = 'F'; // char is single-quoted bool isEmployed = true; // true(non-zero) or false(0) unsigned short numOfsons = 2; // [0, 255] short yearOfAppt = 2009; // [-32767, 32768] unsigned int YearlyPackage = 1500000; // [0, 4294967295] double height = 79.48; // With fractional part float gpa = 4.69f; // Need suffix 'f' for float long totalDrawan = 12047235L; // Suffix 'L' for long long long balance = 995324987LL; // Need suffix 'LL' for long long int cout << " The Gender is : " << gender << endl; cout << " Is she married? : " << isEmployed << endl; cout << " Number of sons she has : " << numOfsons << endl; cout << " Year of her appointment : " << yearOfAppt << endl; cout << " Salary for a year : " << YearlyPackage << endl; cout << " Height is : " << height << endl; cout << " GPA is " << gpa << endl; cout << " Salary drawn upto : " << totalDrawan << endl; cout << " Balance till : " << balance << endl; return 0; }
Sample Output:
Check whether the primitive values crossing the limits or not : -------------------------------------------------------------------- The Gender is : F Is she married? : 1 Number of sons she has : 2 Year of her appointment : 2009 Salary for a year : 1500000 Height is : 79.48 GPA is 4.69 Salary drawn upto : 12047235 Balance till : 995324987
Exercise 7 Solution
Sample C++ Code:
#include <iostream> #include <iomanip> // formatting floating-point numbers with 1 decimal place using namespace std; int main() { int m1 = 5, m2 = 7; double d1 = 3.7, d2 = 8.0; cout << "\n\n Display arithmetic operations with mixed data type :\n"; cout << "---------------------------------------------------------\n"; cout << fixed << setprecision(1); cout <<" "<< m1 << " + " << m2 << " = " << m1+m2 << endl; cout <<" "<< d1 << " + " << d2 << " = " << d1+d2 << endl; cout <<" "<< m1 << " + " << d2 << " = " << m1+d2 << endl; cout <<" "<< m1 << " - " << m2 << " = " << m1-m2 << endl; cout <<" "<< d1 << " - " << d2 << " = " << d1-d2 << endl; cout <<" "<< m1 << " - " << d2 << " = " << m1-d2 << endl; cout <<" "<< m1 << " * " << m2 << " = " << m1*m2 << endl; cout <<" "<< d1 << " * " << d2 << " = " << d1*d2 << endl; cout <<" "<< m1 << " * " << d2 << " = " << m1*d2 << endl; cout <<" "<< m1 << " / " << m2 << " = " << m1/m2 << endl; cout <<" "<< d1 << " / " << d2 << " = " << d1/d2 << endl; cout <<" "<< m1 << " / " << d2 << " = " << m1/d2 << endl; cout << endl; return 0; }
Sample Output:
Display arithmetic operations with mixed data type : --------------------------------------------------------- 5 + 7 = 12 3.7 + 8.0 = 11.7 5 + 8.0 = 13.0 5 - 7 = -2 3.7 - 8.0 = -4.3 5 - 8.0 = -3.0 5 * 7 = 35 3.7 * 8.0 = 29.6 5 * 8.0 = 40.0 5 / 7 = 0 3.7 / 8.0 = 0.5 5 / 8.0 = 0.6
Exercise 8 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { cout << "\n\n Check overflow/underflow during various arithmetical operation :\n"; cout << " Range of int is [-2147483648, 2147483647]"<< endl; cout << "---------------------------------------------------------------------\n"; int n1 = 2147483647; // maximum range of integer cout <<" Overflow the integer range and set in minimum range : " << n1 + 1 << endl; cout <<" Increasing from its minimum range : " << n1 + 2 << endl; cout <<" Product is :" << n1 * n1 << endl; int n2 = -2147483648; // minimum range of integer cout <<" Underflow the range and set in maximum range : " << n2 - 1 << endl; cout <<" Decreasing from its maximum range : " << n2 - 2 << endl; cout <<" Product is : " << n2 * n2 << endl; cout << endl; return 0; }
Sample Output:
Check overflow/underflow during various arithmetical operation : Range of int is [-2147483648, 2147483647] --------------------------------------------------------------------- Overflow the integer range and set in minimum range : -2147483648 Increasing from its minimum range : -2147483647 Product is :1 Underflow the range and set in maximum range : 2147483647 Decreasing from its maximum range : 2147483646 Product is : 0
Exercise 9 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { int num = 57; cout << "\n\n Display the operation of pre and post increment and decrement :\n"; cout << "--------------------------------------------------------------------\n"; cout <<" The number is : " << num << endl; num++; // increase by 1 (post-increment) cout <<" After post increment by 1 the number is : " << num << endl; ++num; // increase by 1 (pre-increment) cout <<" After pre increment by 1 the number is : " << num << endl; num = num + 1; // num is now increased by 1. cout <<" After increasing by 1 the number is : " << num << endl; // 79 num--; // decrease by 1 (post-decrement) cout <<" After post decrement by 1 the number is : " << num << endl; --num; // decrease by 1 (pre-decrement) cout <<" After pre decrement by 1 the number is : " << num << endl; num = num - 1; // num is now decreased by 1. cout <<" After decreasing by 1 the number is : " << num << endl; cout << endl; return 0; }
Sample Output:
Display the operation of pre and post increment and decrement : -------------------------------------------------------------------- The number is : 57 After post increment by 1 the number is : 58 After pre increment by 1 the number is : 59 After increasing by 1 the number is : 60 After post decrement by 1 the number is : 59 After pre decrement by 1 the number is : 58 After decreasing by 1 the number is : 57
Exercise 10 Solution
Sample C++ Code:
#include <iostream> #include <iomanip> // Needed to do formatted I/O using namespace std; int main() { cout << "\n\n Formatting the output :\n"; cout << "----------------------------\n"; double pi = 3.14159265; // this is floating point number cout << fixed << setprecision(4); // number is set to display with 4 decimal places cout <<" The value of pi : " << pi << endl; cout << " The value of pi 4 decimal place of total width 8 : |" << setw(8) << pi << "|" << endl; // setw() sets the total width cout << " The value of pi 4 decimal place of total width 10 : |" << setw(10) << pi << "|"<< endl; cout << setfill('-'); // setfill() sets to fill the blanks with specified character cout << " The value of pi 4 decimal place of total width 8 : |" << setw(8) << pi << "|" << endl; cout << " The value of pi 4 decimal place of total width 10 : |" << setw(10) << pi << "|"<< endl; cout << scientific; // set value in scientific format with exponent cout <<" The value of pi in scientific format is : " << pi << endl; bool done = false; // this is boolean variable cout <<" Status in number : " << done << endl; cout << boolalpha; // set output in alphabet true or false cout <<" Status in alphabet : " << done << endl; cout << endl; return 0; }
Sample Output:
Formatting the output : ---------------------------- The value of pi : 3.1416 The value of pi 4 decimal place of total width 8 : | 3.1416| The value of pi 4 decimal place of total width 10 : | 3.1416| The value of pi 4 decimal place of total width 8 : |--3.1416| The value of pi 4 decimal place of total width 10 : |----3.1416| The value of pi in scientific format is : 3.1416e+00 Status in mumber : 0 Status in alphabet : false
Exercise 11 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { cout << "\n\n Print the result of some specific operation :\n"; cout << "--------------------------------------------------\n"; cout << " Result of 1st expression is : "<< (-1+4*6) <<"\n" ; //-1 + 24 = 23 cout << " Result of 2nd expression is : "<< ((35+5)%7) <<"\n" ; //40 % 7 = 5 (remainder of 40/7) cout << " Result of 3rd expression is : "<< (14+-4*6/11) <<"\n" ; //14 - (24/11)= 14 - 2 = 12 cout << " Result of 4th expression is : "<< (2+15/6*1-7%2) <<"\n\n" ; //2 + (15/6) - remainder of (7/2) = 2 + 2 - 1 = 4 - 1 = 3 }
Sample Output:
Print the result of some specific operation : -------------------------------------------------- Result of 1st expression is : 23 Result of 2nd expression is : 5 Result of 3rd expression is : 12 Result of 4th expression is : 3
Exercise 12 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { int num1, num2, sum; cout << "\n Sum of two numbers :\n"; cout << "-------------------------\n"; cout << " Input 1st number : "; cin >> num1 ; cout << " Input 2nd number : "; cin >> num2; sum = num1 + num2; cout <<" The sum of the numbers is : " << sum << endl; cout << endl; return 0; }
Sample Output:
Sum of two numbers : ------------------------- Input 1st number : 25 Input 2nd number : 39 The sum of the numbers is : 64
Exercise 13 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { cout << "\n\n Swap two numbers :\n"; cout << "-----------------------\n"; int num1, num2, temp; cout << " Input 1st number : "; cin >> num1 ; cout << " Input 2nd number : "; cin >> num2; temp=num2; num2=num1; num1=temp; cout << " After swapping the 1st number is : "<< num1 <<"\n" ; cout << " After swapping the 2nd number is : "<< num2 <<"\n\n" ; }
Sample Output:
Swap two numbers : ----------------------- Input 1st number : 25 Input 2nd number : 39 After swapping the 1st number is : 39 After swapping the 2nd number is : 25
Exercise 14 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { int rad1; float volsp; cout << "\n\n Calculate the volume of a sphere :\n"; cout << "---------------------------------------\n"; cout<<" Input the radius of a sphere : "; cin>>rad1; volsp=(4*3.14*rad1*rad1*rad1)/3; cout<<" The volume of a sphere is : "<< volsp << endl; cout << endl; return 0; }
Sample Output:
Calculate the volume of a sphere : --------------------------------------- Input the radius of a sphere : 6 The volume of a sphere is : 904.32
Exercise 15 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { int sid1; float volcu; cout << "\n\n Calculate the volume of a cube :\n"; cout << "---------------------------------------\n"; cout<<" Input the side of a cube : "; cin>>sid1; volcu=(sid1*sid1*sid1); cout<<" The volume of a cube is : "<< volcu << endl; cout << endl; return 0; }
Sample Output:
Calculate the volume of a cube : --------------------------------------- Input the side of a cube : 5 The volume of a cube is : 125
Exercise 16 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { int rad1,hgt; float volcy; cout << "\n\n Calculate the volume of a cylinder :\n"; cout << "-----------------------------------------\n"; cout<<" Input the radius of the cylinder : "; cin>>rad1; cout<<" Input the height of the cylinder : "; cin>>hgt; volcy=(3.14*rad1*rad1*hgt); cout<<" The volume of a cylinder is : "<< volcy << endl; cout << endl; return 0; }
Sample Output:
Calculate the volume of a cylinder : ----------------------------------------- Input the radius of the cylinder : 6 Input the height of the cylinder : 8 The volume of a cylinder is : 904.32
Exercise 17 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { int width, lngth, area, peri; cout << "\n\n Find the Area and Perimeter of a Rectangle :\n"; cout << "-------------------------------------------------\n"; cout<<" Input the length of the rectangle : "; cin>>lngth; cout<<" Input the width of the rectangle : "; cin>>width; area=(lngth*width); peri=2*(lngth+width); cout<<" The area of the rectangle is : "<< area << endl; cout<<" The perimeter of the rectangle is : "<< peri << endl; cout << endl; return 0; }
Sample Output:
Find the Area and Perimeter of a Rectangle : ------------------------------------------------- Input the length of the rectangle : 10 Input the width of the rectangle : 15 The area of the rectangle is : 150 The perimeter of the rectangle is : 50
Exercise 18 Solution
Sample C++ Code:
#include <iostream> #include <math.h> using namespace std; int main() { float side1, side2, side3, area, s; cout << "\n\n Find the area of any triangle using Heron's Formula :\n"; cout << "----------------------------------------------------------\n"; cout<<" Input the length of 1st side of the triangle : "; cin>>side1; cout<<" Input the length of 2nd side of the triangle : "; cin>>side2; cout<<" Input the length of 3rd side of the triangle : "; cin>>side3; s = (side1+side2+side3)/2; area = sqrt(s*(s-side1)*(s-side2)*(s-side3)); cout<<" The area of the triangle is : "<< area << endl; cout << endl; return 0; }
Sample Output:
Find the area of any triangle using Heron's Formula : ---------------------------------------------------------- Input the length of 1st side of the triangle : 5 Input the length of 2nd side of the triangle : 5 Input the length of 3rd side of the triangle : 5 The area of the triangle is : 10.8253
Exercise 19 Solution
Sample C++ Code:
#include <iostream> #define PI 3.14159 using namespace std; int main() { float radius, area, circum; cout << "\n\n Find the area and circumference of any circle :\n"; cout << "----------------------------------------------------\n"; cout<<" Input the radius(1/2 of diameter) of a circle : "; cin>>radius; circum = 2*PI*radius; area = PI*(radius*radius); cout<<" The area of the circle is : "<< area << endl; cout<<" The circumference of the circle is : "<< circum << endl; cout << endl; return 0; }
Sample Output:
Find the area and circumference of any circle : ---------------------------------------------------- Input the radius(1/2 of diameter) of a circle : 5 The area of the circle is : 78.5397 The circumference of the circle is : 31.4159
Exercise 20 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { float frh, cel; cout << "\n\n Convert temperature in Celsius to Fahrenheit :\n"; cout << "---------------------------------------------------\n"; cout << " Input the temperature in Celsius : "; cin >> cel; frh = (cel * 9.0) / 5.0 + 32; cout << " The temperature in Celsius : " << cel << endl; cout << " The temperature in Fahrenheit : " << frh << endl; cout << endl; return 0; }
Sample Output:
Convert temperature in Celsius to Fahrenheit : --------------------------------------------------- Input the temperature in Celsius : 35 The temperature in Celsius : 35 The temperature in Fahrenheit : 95
Exercise 21 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { float frh, cel; cout << "\n\n Convert temperature in Fahrenheit to Celsius :\n"; cout << "---------------------------------------------------\n"; cout << " Input the temperature in Fahrenheit : "; cin >> frh; cel = ((frh * 5.0)-(5.0 * 32))/9; cout << " The temperature in Fahrenheit : " << frh << endl; cout << " The temperature in Celsius : " << cel << endl; cout << endl; return 0; }
Sample Output:
Convert temperature in Fahrenheit to Celsius : --------------------------------------------------- Input the temperature in Fahrenheit : 95 The temperature in Fahrenheit : 95 The temperature in Celsius : 35
Exercise 22 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { float ang1, ang2, ang3; cout << "\n\n Find the third angle of a triangle :\n"; cout << "-----------------------------------------\n"; cout<<" Input the 1st angle of the triangle : "; cin>>ang1; cout<<" Input the 2nd angle of the triangle : "; cin>>ang2; ang3=180-(ang1+ang2); cout << " The 3rd of the triangle is : " << ang3 << endl; cout << endl; return 0; }
Sample Output:
Find the third angle of a triangle : ----------------------------------------- Input the 1st angle of the triangle : 30 Input the 2nd angle of the triangle : 60
Exercise 23 Solution
Sample C++ Code :
#include <iostream> using namespace std; int main() { float kmph, miph; cout << "\n\n Convert kilometers per hour to miles per hour :\n"; cout << "----------------------------------------------------\n"; cout << " Input the distance in kilometer : "; cin >> kmph; miph = (kmph * 0.6213712); cout << " The "<< kmph <<" Km./hr. means "<< miph << " Miles/hr." << endl; cout << endl; return 0; }
Sample Output:
Convert kilometers per hour to miles per hour : ---------------------------------------------------- Input the distance in kilometer : 25 The 25 Km./hr. means 15.5343 Miles/hr.
Exercise 24 Solutions
Sample C++ Code:
#include <iostream> using namespace std; int main() { float kel, frh; cout << "\n\n Convert temperature in Kelvin to Fahrenheit :\n"; cout << "---------------------------------------------------\n"; cout << " Input the temperature in Kelvin : "; cin >> kel; frh = (9.0 / 5) * (kel - 273.15) + 32; cout << " The temperature in Kelvin : " << kel << endl; cout << " The temperature in Fahrenheit : " << frh << endl; cout << endl; return 0; }
Sample Output:
Convert temperature in Kelvin to Fahrenheit : --------------------------------------------------- Input the temperature in Kelvin : 300 The temperature in Kelvin : 300 The temperature in Fahrenheit : 80.33
Exercise 25 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { float kel, cel; cout << "\n\n Convert temperature in Kelvin to Celsius :\n"; cout << "------------------------------------------------\n"; cout << " Input the temperature in Kelvin : "; cin >> kel; cel = kel - 273.15; cout << " The temperature in Kelvin : " << kel << endl; cout << " The temperature in Celsius : " << cel << endl; cout << endl; return 0; }
Sample Output:
Convert temperature in Kelvin to Celsius : ------------------------------------------------ Input the temperature in Kelvin : 300 The temperature in Kelvin : 300 The temperature in Celsius : 26.85
Exercise 26 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { float kel, frh; cout << "\n\n Convert temperature in Fahrenheit to Kelvin :\n"; cout << "---------------------------------------------------\n"; cout << " Input the temperature in Fahrenheit : "; cin >> frh; kel = (5.0 / 9) * (frh - 32) + 273.15; cout << " The temperature in Fahrenheit : " << frh << endl; cout << " The temperature in Kelvin : " << kel << endl; cout << endl; return 0; }
Sample Output:
Convert temperature in Kelvin to Celsius : ------------------------------------------------ Input the temperature in Kelvin : 300 The temperature in Kelvin : 300 The temperature in Celsius : 26.85
Exercise 27 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { float kel, cel; cout << "\n\n Convert temperature in Celsius to Kelvin :\n"; cout << "---------------------------------------------------\n"; cout << " Input the temperature in Celsius : "; cin >> cel; kel = cel + 273.15; cout << " The temperature in Celsius : " << cel << endl; cout << " The temperature in Kelvin : " << kel << endl; cout << endl; return 0; }
Sample Output:
Convert temperature in Celsius to Kelvin : --------------------------------------------------- Input the temperature in Celsius : 26.85 The temperature in Celsius : 26.85 The temperature in Kelvin : 300
Exercise 28 Solution
Sample C++ Code:
#include <iostream> #include <math.h> #define PI 3.14159 using namespace std; int main() { float side1, side2, ang1, area; cout << "\n\n Find the area of Scalene Triangle :\n"; cout << "----------------------------------------\n"; cout<<" Input the length of a side of the triangle : "; cin>>side1; cout<<" Input the length of another side of the triangle : "; cin>>side2; cout<<" Input the angle between these sides of the triangle : "; cin>>ang1; area = (side1 * side2 * sin((PI/180)*ang1))/2; cout<<" The area of the Scalene Triangle is : "<< area << endl; cout << endl; return 0; }
Sample Output:
Find the area of Scalene Triangle : ---------------------------------------- Input the length of a side of the triangle : 5 Input the length of another side of the triangle : 6 Input the angle between these sides of the triangle : 6 The area of the Scalene Triangle is : 1.56793
Exercise 29 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { int dividend, divisor, quotient,remainder; cout << "\n\n Compute quotient and remainder :\n"; cout << "-------------------------------------\n"; cout<<" Input the dividend : "; cin>>dividend; cout<<" Input the divisor : "; cin>>divisor; quotient=dividend / divisor; remainder=dividend % divisor; cout<<" The quotient of the division is : "<< quotient << endl; cout<<" The remainder of the division is : "<< remainder << endl; cout << endl; return 0; }
Sample Output:
Compute quotient and remainder : ------------------------------------- Input the dividend : 25 Input the divisor : 3 The quotient of the division is : 8 The remainder of the division is : 1
Exercise 30 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { float n1,n2,n3,n4,tot,avrg; cout << "\n\n Compute the total and average of four numbers :\n"; cout << "----------------------------------------------------\n"; cout<<" Input 1st two numbers (separated by space) : "; cin>> n1 >> n2; cout<<" Input last two numbers (separated by space) : "; cin>> n3 >> n4; tot=n1+n2+n3+n4; avrg=tot/4; cout<<" The total of four numbers is : "<< tot << endl; cout<<" The average of four numbers is : "<< avrg << endl; cout << endl; return 0; }
Sample Output:
Compute the total and average of four numbers : ---------------------------------------------------- Input 1st two numbers (separated by space) : 25 20 Input last two numbers (separated by space) : 15 25 The total of four numbers is : 85 The average of four numbers is : 21.25
Exercise 31 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { int x; cout << "\n\n Make a rectangular shape by a single digit number :\n"; cout << "--------------------------------------------------------\n"; cout<<" Input the number : "; cin>> x; cout<<" "<<x<<x<<x<<x<<endl; cout<<" "<<x<<" "<<" "<<x<<endl; cout<<" "<<x<<" "<<" "<<x<<endl; cout<<" "<<x<<" "<<" "<<x<<endl; cout<<" "<<x<<" "<<" "<<x<<endl; cout<<" "<<x<<x<<x<<x<<endl; cout << endl; return 0; }
Sample Output:
Make a rectangular shape by a single digit number : -------------------------------------------------------- Input the number : 5 5555 5 5 5 5 5 5 5 5 5555
Exercise 32 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { signed long num1 = 0; cout << "\n\n Check whether a number is positive, negative or zero :\n"; cout << "-----------------------------------------------------------\n"; cout << " Input a number : "; cin >> num1; if(num1 > 0) { cout << " The entered number is positive.\n\n"; } else if(num1 < 0) { cout << " The entered number is negative.\n\n"; } else { std::cout << " The number is zero.\n\n"; } return 0; }
Sample Output:
Check whether a number is positive, negative or zero : ----------------------------------------------------------- Input a number : 8 The entered number is positive.
Exercise 33 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { cout << "\n\n Divide two numbers and print:\n"; cout << "----------------------------------\n"; int a; int b; int resdiv; a=30; b=10; resdiv=a/b; cout << " The quotient of "<< a << " and "<<b <<" is : "<< resdiv <<"\n\n" ; }
Sample Output:
Divide two numbers and print: ---------------------------------- The quotient of 30 and 10 is : 3
Exercise 34 Solution
Sample C++ Code:
#include<iostream> #include<cmath> #include <ctime> using namespace std; int main() { time_t t = time(NULL); tm* tPtr = localtime(&t); cout << "\n\n Display the Current Date and Time :\n"; cout << "----------------------------------------\n"; cout << " seconds = " << (tPtr->tm_sec) << endl; cout << " minutes = " << (tPtr->tm_min) << endl; cout << " hours = " << (tPtr->tm_hour) << endl; cout << " day of month = " << (tPtr->tm_mday) << endl; cout << " month of year = " << (tPtr->tm_mon)+1 << endl; cout << " year = " << (tPtr->tm_year)+1900 << endl; cout << " weekday = " << (tPtr->tm_wday )<< endl; cout << " day of year = " << (tPtr->tm_yday )<< endl; cout << " daylight savings = " <<(tPtr->tm_isdst )<< endl; cout << endl; cout << endl; cout << " Current Date: " <<(tPtr->tm_mday)<<"/"<< (tPtr->tm_mon)+1 <<"/"<< (tPtr->tm_year)+1900<< endl; cout << " Current Time: " << (tPtr->tm_hour)<<":"<< (tPtr->tm_min)<<":"<< (tPtr->tm_sec) << endl; cout << endl; return 0; }
Sample Output:
Display the Current Date and Time :
----------------------------------------
seconds = 57
minutes = 33
hours = 12
day of month = 6
month of year = 7
year = 2017
weekday = 4
day of year = 186
daylight savings = 0
Current Date: 6/7/2017
Current Time: 12:33:57 Exercise 35 Solution
Sample C++ Code:
#include <iostream> using namespace std; int main() { cout << "\n\n Compute the specified expressions and print the output:\n"; cout << "------------------------------------------------------------\n"; cout << " Result of the expression "<<"(25.5 * 3.5 - 3.5 * 3.5) / (40.5 - 4.5) is : "<< (25.5 * 3.5 - 3.5 * 3.5) / (40.5 - 4.5) <<"\n" ; }
Sample Output:
Compute the specified expressions and print the output: ------------------------------------------------------------ Result of the expression (25.5 * 3.5 - 3.5 * 3.5) / (40.5 - 4.5) is : 2.13889
Exercise 36 Solution
Sample C++ Code:
#include <iostream> #include <iomanip> using namespace std; int main() { cout << "\n\n Formatting the output using type casting:\n"; cout << "----------------------------------------------\n"; cout<<"Print floating-point number in fixed format with 1 decimal place: "; cout << fixed << setprecision(1); cout<<"\nTest explicit type casting :\n"; int i1 = 4, i2 = 8; cout << i1 / i2 << endl; cout << (double)i1 / i2 << endl; cout << i1 / (double)i2 << endl; cout << (double)(i1 / i2) << endl; double d1 = 5.5, d2 = 6.6; cout<<"\nTest implicit type casting :\n" ; cout << (int)d1 / i2 << endl; cout << (int)(d1 / i2) << endl; cout <<"\nint implicitly casts to double: \n"; d1 = i1; cout << d1 << endl; // 4.0 cout<<"double truncates to int!: \n"; i2 = d2; cout << i2 << endl; // 6 }
Sample Output:
Formatting the output using type casting:
----------------------------------------------
Print floating-point number in fixed format with 1 decimal place:
Test explicit type casting :
0
0.5
0.5
0.0
Test implict type casting :
0
0
int implicitly casts to double:
4.0
double truncates to int!:
6