Evaluate a Polynomial for a Given Value

We have already learned how to evaluate expressions. Since polynomials are expressions, we'll follow the same procedures to evaluate a polynomial. We will substitute the given value for the variable and then simplify using the order of operations.

Example 6.13

Evaluate \(5 x^{2}-8 x+4\) when

  1. \(x=4\)
  2. \(x=−2\)
  3. \(x=0\)
Solution
  1. \(x=4\)
 
  \(5 x^{2}-8 x+4\)
Substitute \(4\) for \(x\). \(5(4)^{2}-8(4)+4\)
Simplify the exponents. \(5 \cdot 16-8(4)+4\)
Multiply. \(80-32+4\)
Simplify. \(52\)

 

  1. \(x=−2\)
 
  \(5 x^{2}-8 x+4\)
Substitute \(-2\) for \(x\). \(5(-2)^{2}-8(-2)+4\)
Simplify the exponents. \(5 \cdot 4-8(-2)+4\)
Multiply. \(20+16+4\)
Simplify. \(40\)

  1. \(x=0\)
 
  \(5 x^{2}-8 x+4\)
Substitute \(0\) for \(x\). \(5(0)^{2}-8(0)+4\)
Simplify the exponents. \(5 \cdot 0-8(0)+4\)
Multiply. \(0+0+4\)
Simplify. \(4\)
Try It 6.25

Evaluate: \(3 x^{2}+2 x-15\) when

  1. \(x=3\)
  2. \(x=−5\)
  3. \(x=0\)
Try It 6.26

Evaluate: \(5 z^{2}-z-4\) when

  1. \(z=−2\)
  2. \(z=0\)
  3. \(z=2\)

Example 6.14

The polynomial \(-16 t^{2}+250\) gives the height of a ball \(t\) seconds after it is dropped from a 250 foot tall building. Find the height after \(t=2\) seconds.

Solution
  \(-16 t^{2}+250\)
Substitute \(t=2\). \(-16(2)^{2}+250\)
Simplify. \(-16 \cdot 4+250\)
Simplify. \(-64+250\)
Simplify. \(186\)
  After 2 seconds the height of the ball is 186 feet.
Try It 6.27

The polynomial \(-16 t^{2}+250\) gives the height of a ball \(t\) seconds after it is dropped from a 250-foot tall building. Find the height after \(t=0\) seconds.

Try It 6.28

The polynomial \(−16t2+250\) gives the height of a ball \(t\) seconds after it is dropped from a 250-foot tall building. Find the height after \(t=3\) seconds.

Example 6.15

The polynomial \(6 x^{2}+15 x y\) gives the cost, in dollars, of producing a rectangular container whose top and bottom are squares with side \(x\) feet and sides of height \(y\) feet. Find the cost of producing a box with \(x=4\) feet and \(y=6\) feet.

Solution
  \(6 x^{2}+15 x y\)
Substitute \(x=4, y=6\) \(6(4)^{2}+15(4)(6)\)
Simplify. \(6 \cdot 16+15(4)(6)\)
Simplify. \(96+360\)
Simplify. \(456\)
  The cost of producing the box is $456.
Try It 6.29

The polynomial \(6 x^{2}+15 x y\) gives the cost, in dollars, of producing a rectangular container whose top and bottom are squares with side \(x\) feet and sides of height \(y\) feet. Find the cost of producing a box with \(x=6\) feet and \(y=4\) feet.

Try It 6.30

The polynomial \(6 x^{2}+15 x y\) gives the cost, in dollars, of producing a rectangular container whose top and bottom are squares with side \(x\) feet and sides of height \(y\) feet. Find the cost of producing a box with \(x=5\) feet and \(y=8\) feet.