Factor Trinomials of the form ax2 + bx + c with a GCF

Now that we have organized what we've covered so far, we are ready to factor trinomials whose leading coefficient is not 1, trinomials of the form \(a x^{2}+b x+c\).

Remember to always check for a GCF first! Sometimes, after you factor the GCF, the leading coefficient of the trinomial becomes 1 and you can factor it by the methods in the last section. Let's do a few examples to see how this works.

Watch out for the signs in the next two examples.

Example 7.30

Factor completely: \(2 n^{2}-8 n-42\).

Solution

Use the preliminary strategy.

Is there a greatest common factor?

Yes, GCF = 2. Factor it out.

\(2 n^{2}-8 n-42\)

\(2\left(n^{2}-4 n-21\right)\)

Inside the parentheses, is it a binomial, trinomial, or are there more than three terms?

It is a trinomial whose coefficient is 1, so undo FOIL.

Use 3 and −7 as the last terms of the binomials.

\(2(n)(n)\)

\(2(n+3)(n-7)\)

 

Factors of −21 Sum of factors
\(1, −21\) \(1+(−21)=−20\)
\(3,−7\) \(3+(−7)=−4\ *\)


Check.

\(2(n+3)(n-7)\)

\(2\left(n^{2}-7 n+3 n-21\right)\)

\(2\left(n^{2}-4 n-21\right)\)

\(2 n^{2}-8 n-42 \text{✓}\)

Try It 7.59

Factor completely: \(4 m^{2}-4 m-8\).

Try It 7.60

Factor completely: \(5 k^{2}-15 k-50\).

Example 7.31

Factor completely: \(4 y^{2}-36 y+56\).

Solution

Use the preliminary strategy.

Is there a greatest common factor?

Yes, GCF = 4. Factor it.

\(4 y^{2}-36 y+56\)

\(4\left(y^{2}-9 y+14\right)\)

Inside the parentheses, is it a binomial, trinomial, or are there more than three terms?

It is a trinomial whose coefficient is 1. So undo FOIL.

 

 

\(4(y \qquad)(y \qquad)\)

Use a table like the one below to find two numbers that multiply to 14 and add to −9.  
Both factors of 14 must be negative. \(4(y-2)(y-7)\)

 

Factors of 14 Sum of factors
\(−1,−14\) \(−1+(−14)=−15\)
\(−2,−7\) \(−2+(−7)=−9*\)


Check.

\(4(y-2)(y-7)\)

\(4\left(y^{2}-7 y-2 y+14\right)\)

\(4\left(y^{2}-9 y+14 \text{✓}\right)\)

Try It 7.61

Factor completely: \(3 r^{2}-9 r+6\).

Try It 7.62

Factor completely: \(2 t^{2}-10 t+12\).

In the next Example the GCF will include a variable.

Example 7.32

Factor completely: \(4 u^{3}+16 u^{2}-20 u\).

Solution

Use the preliminary strategy.

Is there a greatest common factor?

Yes, GCF = 4u. Factor it.

\(4 u^{3}+16 u^{2}-20 u\)

\(4 u\left(u^{2}+4 u-5\right)\)

Binomial, trinomial, or more than three terms?

It is a trinomial. So "undo FOIL".

 

\(4 u(u)(u)\)

Use a table like the table below to find two numbers that multiply to -5 and add to 4. \(4 u(u-1)(u+5)\)


Factors of −5 Sum of factors
\(−1,5\) \(−1+5=4*\)
\(1,−5\) \(1+(−5)=−4\)


Check.

\(4 u(u-1)(u+5)\)

\(4 u\left(u^{2}+5 u-u-5\right)\)

\(4 u\left(u^{2}+4 u-5\right)\)

\(4 u^{3}+16 u^{2}-20 u\text{✓}\)

Try It 7.63

Factor completely: \(5 x^{3}+15 x^{2}-20 x\).

Try It 7.64

Factor completely: \(6 y^{3}+18 y^{2}-60 y\).